Question

Factor: 2x^2-5x-3=0

Answer 1

I can never remember the steps for factoring when the first term has a number in front of it, can someone remind me?

Answer 2

Split the middle term into two parts such that the product of the two parts is equal to -6 and sum is equal to -5

Answer 3

2x^2-6x+x-3

Answer 4

(2x^2-6x)+(x-3)

Take common now

Answer 5

2x(x-3)+(x-3)?

Answer 6

@jiteshmeghwal9

Answer 7

Yes now take (x-3) common

Answer 8

So one of the answers is 3, but how do I find the other answer?

Answer 9

The book says the other answer is supposed to be -1/2

Answer 10

(x-3)(2x+1)=0

Answer 11

How did you get the 2x+1?

Answer 12

2x(x-3)+(x-3)=0
After taking x-3 common
X
(X-3)(2x+1)=0

Answer 13

Sorry I'm not understanding what you mean by taking x-3 common

Answer 14

Okay assume x-3=t
So
2x(x-3)+(x-3) becomes 2xt+t

Answer 15

Taking t common
T(2x+1)=0
(X-3)(2x+1)=0

Answer 16

Okay I think I kind of get it.

Answer 17

Thank you for all your help!

Answer 18

U really got it ?

Answer 19

Yeah I think so. I just need to keep practicing.

Answer 20

Yup best of luck