Question

Solve for p.

3+|1+p|=123+|1+p|=12



a.p = 8 or p=−10p=−10

b.p = 14 or p=−16p=−16

c.p = 10 or p=−10p=−10

d.p = 8 or p=−8

Answer 1

3+|1+p|=12 sorry for the confusion

Answer 2

Ok so when we have absolute values, what do you have to do first before touching anything inside the brackets?

Answer 3

um subtract 3 from 12 right

Answer 4

Yes so we have \[\left| 1+p \right|=9\]

Answer 5

And if \[\left| a \right|=a\] or \[\left| a \right|=-a\] What do you think we do next?

Answer 6

subtracting or adding

Answer 7

\[\left| 1+p \right|=9\] becomes\[1+p=9\]and\[1-p=9\] right?

Answer 8

yea and i subtact 1 from 9 right

Answer 9

Yes so p can equal 8 or?

Answer 10

-8 THANKS ALOT KOOKIE

Answer 11

ya boi

Answer 12

wrong

Answer 13

thank you benji it was right