PRECALC help will fan and medal and attach the problem
You get the inverse of a function by reflecting it over the line y=x. (You may reacall from algebra that sometimes when want to find the inverse of a function and you switch y and x and solve for y because y=x.)
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So, let's say you have the point (3,0). It's inverse would be (0,3). You just switch x and y. |dw:1474496889027:dw|
k i think im kinda getting it
Because the inverse of a graph is reflected over the y-axis, the y-axis is the line of symmetry. So the function (graph) and its inverse are symmetrical about the y-axis. (You can elminate the 2nd answer choice).
ok
Then if you draw in or imagine the line y=x there and turn you head, you can see that graph f is definitely not symmetrical with graph h over the line y=x.
mhm
ohh ok so then it would be g
ohh ok
Ok I confused myself. So the answer is that f and g are inverses symmetrical about the line y=x. (Choice 3)
And you can check with the point (3,6), which is on graph f. It's inverse, (6,3), is also on graph g.
so is that the answer?
Yes
ok thank you so much i think i have another question could you help me with that too?
Sure I can try
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