OpenStudy (nvidiaintely):

Given the following chemical equation, if 162.0 grams of potassium reacts with excess oxygen gas and was found to produce 172 grams of potassium oxide, what is the percent yield for this reaction? 4 K(s) + O2(g) arrow 2K2O(s) 44% 75% 22% 88%

1 year ago
OpenStudy (nvidiaintely):

@Google @Kevin @ScribblePikachu

1 year ago
OpenStudy (nvidiaintely):

@Will.H Can someone help me with this?

1 year ago
OpenStudy (natalief):

can you provide the relative atomic mass of Potassium???

1 year ago
OpenStudy (nvidiaintely):

39.0983

1 year ago
OpenStudy (scribblepikachu):

i would say 88%

1 year ago
OpenStudy (kevin):

I'm sorry. I really don't know what is the 'percent yield' means. I need to see how the other people solve this kind of question. So I can solve this too.

1 year ago
OpenStudy (natalief):

yes it is 88%

1 year ago
OpenStudy (nvidiaintely):

Thanks. How did you get there @ScribblePikachu?

1 year ago
OpenStudy (natalief):

@Kevin Percentage yield is dividing the mass of the actual yield by the mass of theorectical yield and then x100%

1 year ago
OpenStudy (scribblepikachu):

188.4 gram of K2O should be formed for 100% yield then in this case 172 gram is formed 188.4 gram = 100 % 172 gram = 100*172 / 188.4 = 91.3 % but the closest to that is 88% so it should be 88% if not it would be lower than that meaning it would had been the exsact % of the other ones

1 year ago
OpenStudy (nvidiaintely):

T H A N K Y O U !

1 year ago
OpenStudy (scribblepikachu):

np

1 year ago
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