Question

Given the following chemical equation, if 162.0 grams of potassium reacts with excess oxygen gas and was found to produce 172 grams of potassium oxide, what is the percent yield for this reaction?
4 K(s) + O2(g) arrow 2K2O(s)

44%

75%

22%

88%

Answer 1

@Google @Kevin @ScribblePikachu

Answer 2

@Will.H Can someone help me with this?

Answer 3

can you provide the relative atomic mass of Potassium???

Answer 4

39.0983

Answer 5

i would say 88%

Answer 6

I'm sorry. I really don't know what is the 'percent yield' means.
I need to see how the other people solve this kind of question. So I can solve this too.

Answer 7

yes it is 88%

Answer 8

Thanks.
How did you get there @ScribblePikachu?

Answer 9

@Kevin Percentage yield is dividing the mass of the actual yield by the mass of theorectical yield and then x100%

Answer 10

188.4 gram of K2O should be formed for 100% yield
then in this case 172 gram is formed
188.4 gram = 100 %
172 gram = 100*172 / 188.4 = 91.3 % but the closest to that is 88% so it should be 88% if not it would be lower than that meaning it would had been the exsact % of the other ones

Answer 11

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a.
1004072-01-01-03-00_files/i0150001.jpg cm
c.
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b.
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