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Physics 21 Online
OpenStudy (irishboy123):

About electrics

OpenStudy (irishboy123):

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OpenStudy (irishboy123):

@ljetibo @Issy14 @SapphireMoon @osprey

OpenStudy (irishboy123):

So that means that the charge is actually evenly distributed

OpenStudy (issy14):

Because the electrons do not move correct.

OpenStudy (irishboy123):

i think that's right

OpenStudy (irishboy123):

so Gaussian Surface or what?

OpenStudy (irishboy123):

2R is outside the sphere

OpenStudy (ljetibo):

thnx for transcribing the question. Much easier this way. Yeah, someone would have to pick a shell as a gaussian surface and then do the integrals. I know that there will be 2 solutions right now: 1) when your r is bigger than R, then the electric field will be as if you're dealing with a point charge in the center of the sphere and 2) when your r is less than R, then electric field's gonna be something funky looking.

OpenStudy (irishboy123):

i'm seeing: linear for \(r <R\), inverse square for \(x>R\) with hindsight, not sure it helps on the original qu, though

OpenStudy (irishboy123):

yep, that was just BS !!

OpenStudy (issy14):

thank you very much

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