Question

One more question (for now)

Answer 1

\(f(x) = 2 + \dfrac3x + \dfrac4{x^2}\)

I have to find the derivative again

Answer 2

@ganeshie8

Answer 3

I'm not sure how to start this one

Answer 4

\[(f+g)' = f' + g'\]

Simply differentiate term by term

Answer 5

I think I got it, 3/x is the same as 3x^-1 and 4/x^2 is the same as 4x^-2

Answer 6

That's a good start

Answer 7

\(-3x^{-2} - 8x^{-3}\)
\(f'(x) = \dfrac{-3}{x^2} - \dfrac8{x^2}\)?

Answer 8

Don't you mean -3/x^2 - 8/x^3 ?

Answer 9

Whoops, yep :)

Answer 10

then it looks perfect! lets also check w/ woflram
http://www.wolframalpha.com/input/?i=(2+%2B+%5Cdfrac3x+%2B+%5Cdfrac4%7Bx%5E2%7D)%27

Answer 11

Good job!