Question

(Medal)
Solve for n:
n * (n-4)! = (n-1)!

I simplified an equation down to this and I'm not sure how to get rid of the factorial.

Answer 1

Well let's make sure you're familiar with how factorials work.
If I have something like \(\large\rm 7!\),
does it make sense that I can pull the 7 out of that expression and rewrite it this way?
\(\large\rm 7!=7\cdot6!\)

Answer 2

Yes

Answer 3

So based on that logic I can do
n * (n-4)! = (n-1)(n-2)(n-3)(n-4)! and cancel out the (n-4)!

Like that?

Answer 4

Yes, good :)

Answer 5

Awesome.