Question

*cough* Medals *cough*

Answer 1

May I help?

Answer 2

sure

Answer 3

Ok

Answer 4

Recall law's of exponents:
\(b^x\times b^y=b^{x+y}\)
\(b^x\div b^y=b^{x-y}\)
\((b^x)^y=b^{xy}\)

Answer 5

As you and me know that the a number of power a raised to the power b, the result will be the same base with the multiplication of powers.
i.e
\[(x^a)^b=x^{a \times b}=x^{ab}\]

Answer 6

Thanks, mathmate!

Answer 7

So sam?

Answer 8

Yes. Sam has the correct answer!

Answer 9

yay, which one of you want the medal?

Answer 10

You give him.
He gives me.
I give you.

hahah

Answer 11

Medals don't matter.
What matters is that got the idea and can solve such this yourself.

Answer 12

that you are correct

Answer 13

For me, I won't ask for a medal!