Question

s

Answer 1

si the only negative options are -1 and -2 cause it would have to be a negative value i think but idk how to determine the actual number @calculusxy

Answer 2

I guess you can solve for a from the vertex form given the vertex of the parabola
\( y = a(x-h)^2 + k\)

Vertex: (1,4)
\(y = a( x - 1)^2 + 4\)

Then choose a point from the graph for example (3,0) -- one of the x-int.
\(0 = a(3-1)^2 + 4\)
\(0 = a(2)^2 + 4\)
\(0 = 4a + 4\)
\(-4 = 4a\)
\(-1 = a\)

Answer 3

oh okay

Answer 4

there is 1 more

Answer 5

OK

Answer 6

What are the x-ints in the graph?

Answer 7

3 -1

Answer 8

c?

Answer 9

Is this question with only one answer or can you choose more?

Answer 10

But yes C is a possible answer