Question

When x = 3 and y = 5, by how much does the value of 3x2 – 2y exceed the value of 2x2 – 3y ?

Individual Question

4


14


16


20


50

Answer 1

@tigerlover @T-Dawg02

Answer 2

can someone give me a medal, I need 1 and then I can get a thing

Answer 3

At x=3 and y=5:
3x^2-2y = 27-10 = 17
2x^2-3y = 18-15 = 3
17-3 = 14

Answer 4

Could you explain in further detail

Answer 5

you plug x = 3 and y = 5 into 3x^2 - 2y and work it out

3(3)^2 - 2(5) = 3*9 - 10 = 27-10 = 17

Answer 6

When the value of x is equal to 3 and the y is equal to 5,

3x^2 – 2y

=> 3*3^2 - 2*5

=> 3*9 - 10 = 17

And 2x^2– 3y

=> 2*3^2 - 3*5

=> 2* 9 - 15 = 3

This gives 3x^2 – 2y exceeding 2x^2– 3y by 17 - 3 = 14

Answer 7

Oooh, thank you very much :)

Answer 8

I can't give yo both a medal sadly

Answer 9

you*

Answer 10

Give it to who ever you want

Answer 11

I have to decide between a cat and a dog

Answer 12

kek

Answer 13

Uh oh, math war incoming

Answer 14

I gtg but thanks for the help.

Answer 15

Np