Question

Medal and fan !!

Answer 1

24-38 evens

Answer 2

Happy to help, but expect you to get started and to share some of your own work first.
In regard to #33: This quadratic equation is not in standard form. Move the 54 from the right side to the left side by subtracting 54 from both sides of the original equation. Type out your result. Next, think of what you have done in the past to factor quadratic equations. What would your first move be?

Answer 3

Thanks but i only have to do 24-38 evens

Answer 4

@zepdrix

Answer 5

\[\large\rm x^2-8x+12=0\]What's going on potassium floride? You gotta solve this? :d

Answer 6

lol yea

Answer 7

Remember how to factor n stuff? D:

Answer 8

yea a little

Answer 9

We need factors of 12,
that add to -8,

12 = -3*-4
Hmm but -3+-4 does not give us -8.

12 = -12*-1
Hmm but -12+-1 does not give us -8.

Any other factors we can try?

Answer 10

6 and 2

Answer 11

6*2=12
6+2=8

Answer 12

Ooo there we go.
-6*-2=12
-6+-2=-8

Answer 13

Ok great so our polynomial will factor as such,\[\large\rm (x-6)(x-2)=0\]

Answer 14

oh ok

Answer 15

is that the answer?

Answer 16

From this nice factored form, we can find our solutions easier.
Apply your Zero-Factor Property:
\(\large\rm (x-6)=0\qquad\) and \(\large\rm \qquad (x-2)=0\)
Solve for x in each case.

Answer 17

ok so (x-6)=0
is x=6

Answer 18

and (x-2)=0
x=2

Answer 19

yay good job

Answer 20

wow thats so easy.. I thought it was so much more complicated

Answer 21

All of the trinomials will work out like that.
34 and 36 will be different though (easier),
notice they only have 2 terms.

Answer 22

30 as well :d

Answer 23

ok so now i have to do number 26... 2 and -35
So what multiply to equal 2 and adds to equal 35... wait nothing

Answer 24

Ooo you're thinking backwards.
`multiply to equal -35`
`add to equal 2`

Answer 25

oh ok

Answer 26

Find two multiples of -35 which are 2 apart from one another.

Answer 27

ok.. um

Answer 28

nothing

Answer 29

uh my brain is hurting

Answer 30

Hmm 35 should be pretty easy XD
it only has one set of non-prime factors

Answer 31

35 = 7*5
and 7 and 5 are 2 units apart, yes?

Answer 32

ohhhhh i was thinking 6 and 5 by accident.. wow i feel so stupid

Answer 33

ok yes your are right

Answer 34

So how do we get -35 and +2.
You gotta work with negatives somehow.

Answer 35

@zepdrix sorry i am confused now

Answer 36

-7+ -5 is -12 not 2

Answer 37

@zepdrix

Answer 38

\(\large\rm -7\cdot-5=35\)
This doesn't give us the -35 that we need.
Multiplying two negatives together gives us a positive.

So I guess this is telling us that ONE OF the values needs to be negative, ya?
\(\large\rm -7\cdot5=-35\)
\(\large\rm 7\cdot-5=-35\)

So we want one of those two sets of numbers.

Answer 39

oh ok got it !

Answer 40

What did u say about what i have to do for questions like 30

Answer 41

@zepdrix

Answer 42

\[\large\rm n^2-6n=0\]Pull the common factor out of each term.
Hmm looks like they have `n` in common, ya?

Answer 43

\[\large\rm n(n-6)=0\]

Answer 44

oh ok and then what @zepdrix

Answer 45

Again, apply your Zero-Factor Property,
setting each individual factor equal to 0,
\(\large\rm n=0\qquad\) and \(\large\rm \qquad(n-6)=0\)
and solve for n in each case.

Answer 46

n=0 and n=6

Answer 47

thats it? wow

Answer 48

yes

Answer 49

what about 34... it doesnt = 0?

Answer 50

@zepdrix