The general form of the equation of a circle is x2 + y2 + 42x + 38y − 47 = 0. The equation of this circle in standard form is....... The center of the circle is at the point........ and its radius is...... units.

Question

jango_in_dtown · Answer

complete the squares.

jango_in_dtown · Answer

$$x^2+y^2+42x+38y-47=0 \implies (x+21)^2+(y+19)^2=47+21^2+19^2$$

jango_in_dtown · Answer

centre is ???

welshfella · Answer

can you find where the centre is from the equation?

bethb · Answer

sorry that was homework for the other day