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OpenStudy (bethb):
The general form of the equation of a circle is x2 + y2 + 42x + 38y − 47 = 0. The equation of this circle in standard form is....... The center of the circle is at the point........ and its radius is...... units.
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OpenStudy (jango_in_dtown):
complete the squares.
OpenStudy (jango_in_dtown):
\[x^2+y^2+42x+38y-47=0 \implies (x+21)^2+(y+19)^2=47+21^2+19^2\]
OpenStudy (jango_in_dtown):
centre is ???
OpenStudy (welshfella):
can you find where the centre is from the equation?
OpenStudy (bethb):
sorry that was homework for the other day
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