Question

When written in standard form, the quadratic equation, x2 - 2x - 35 = 0, is equivalent to y = (x - 1)2 - 36. What is the vertex of the graph of the quadratic equation, x2 - 2x - 35 = 0?

Answer 1

:)

Answer 2

if the equation is written in standard form \[y=a(x-h)^2+k\]
(h,k) is the vertex point \[\large\rm y=(x-1)^2-36\]

Answer 3

can i get an example please

Answer 4

if you are not given the vertex form, you can always calculate it by using \(h=\dfrac{-b}{2a} \) then k would be solved by \(k = \dfrac{4ac-b^2}{4a} \)

Answer 5

\[\large\rm y=a(x-\color{Red}{h})^2 + \color{blue}{k}\]
for example
\[\large\rm y=a(x+2 )^2 +k\]
as you can see if we rewrite in standard form it should be `x-h`
\[\large\rm y=a(x-\color{Red}{(-2)} )^2 +\color{blue}{3}\]
\[(\color{ReD}{h},\color{blue}{k})\]
\[(\color{ReD}{-2},\color{blue}{3})\]
(-2,3) is the vertex

Answer 6

\[\large\rm Ax^\color{Red}{2}+Bx+C=0\]

Answer 7

oh ok thank you