Calculus help http://prntscr.com/cs84of
is there any way you can attach it as a file instead of using a photosharing website? those don't work for me
Revenue = selling price times # sold So you originally have (for pizza) 2.5(1000) But then for every 10 cent increase, they sell 20 fewer slices so you get (2.5+0.1x)(1000-20x) Simplify this
And tell me what you get
@amy0799
2500 +50x-2x^2 @StudyGurl14
yes. Okay, now graph it. The value of y at the maximum value x is your answer
i thought with optimization, you're suppose to have 2 equations
technically you should/can...but I sorta combined them Do you want me to show you?
yes please
@StudyGurl14
You essentially had 2.5 + 0.1x representing the change in price and 1000 - 20x representing the change in costumers. Then you have the revenue equation which is price times amount sold. So you have to combine the two equations to fit the revenue equation, which gets you the appropriate quadratic. This is not a typical optimization question in that we NEED two equations. If they wre asking us the amount of pizzas and amount of sodas we should sell to maximum profit, that sort of question would require at least two functions. but this one doesn't
oh ok. so to do this without graphing it, would you be taking the derivative?
@StudyGurl14
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