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Linear Algebra 22 Online
OpenStudy (vheah):

Are these set of vectors linearly dependent or linearly independent? (1,0,0,0) (1,1,0,0) (1,1,1,0) (1,1,1,1) I say there are independent since I cannot think of any linear combinations to find the other vectors.

OpenStudy (vheah):

Can someone confirm my answer? If I am wrong can someone explain why?

OpenStudy (518nad):

definitely independant

OpenStudy (518nad):

theres an intuitive way to say it is

OpenStudy (518nad):

the more formula way is to take the determinant

OpenStudy (vheah):

so is this the case where I have to make an augmented matrix by multiplying c1(v1), c2(v2) or is that a different situation ?

OpenStudy (518nad):

what do u mean

OpenStudy (518nad):

oh um i see, okay so you mean the formal definition of linear independance

OpenStudy (518nad):

c1v1+c2v2+c3v3+c4v4=0 if c1 to c4 are constants and v1 to v4 are your vectors given if the solution to this equation is such that all c1 to c4 are 0, the only trivial solution, then these vectors are said to be lienarly independant

OpenStudy (vheah):

Yes. So I can do that for the given problem above to prove that it is linearly independent by finding all solutions to be 0 ?

OpenStudy (518nad):

yeah thats hard to do, to check for all combinations

OpenStudy (518nad):

have you heard of determinants?

OpenStudy (518nad):

does your teacher not want u to use determinant

OpenStudy (vheah):

Yup we have covered determinants. How he did it in class was he made an augmented matrix with all 0's at the end (he called it homogenous) and then he solved for the solutions after doing REF

OpenStudy (518nad):

yea i was gonna go into that after the basic method

OpenStudy (518nad):

there are more intuitive ways to do this

OpenStudy (518nad):

one of them is consider the vectors you are given, they are dimension 1,2,3,4, in order

OpenStudy (518nad):

so consider vectors 1 and 2, they haven o dimension 3, so they cant possible effect he 3rd vector in such a way that their can ever give u the 3rd vector

OpenStudy (518nad):

you can think of how to extend htis argument

OpenStudy (518nad):

now another method is like ur prof did, to rewrite your vectors

OpenStudy (vheah):

Yes that makes sense.

OpenStudy (518nad):

u can eliminate a vector and rewrite it as a combination of the other vectors, and that should still be linearly independant

OpenStudy (518nad):

if these 4 were lienarly independant to begin with

OpenStudy (vheah):

okay. So if u were to use the determinant method, does the determinant have to be 0 to indicate that the set of vectors are linearly independent?

OpenStudy (518nad):

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