Question

agent smith

Answer 1

@agent0smith

Answer 2

First expand it out.

Answer 3

okay then what

Answer 4

-4x-24?

Answer 5

sorry i messed that up lol

Answer 6

That's... not close.\[\large f(x) = 2(x-3)(x+4)\]expand it out.

Answer 7

2x^2+2x-24

Answer 8

Much better. That's standard form.

For vertex form, you need to complete the square.

Answer 9

youre gonna have to explain that im sorry lol

Answer 10

I don't feel like explaining it all... you can google completing the square, here are the steps.

\[\large 2x^2+2x-24\] \[\large 2(x^2+x)-24\] \[\large 2(x^2+x+???)-24-2(???)\] \[\large 2(x^2+x+\frac{ 1 }{ 4 })-24-2(\frac{ 1 }{ 4 })\] \[\large 2(x+\frac{ 1 }{ 2 })^2-24-\frac{ 1 }{ 2 }\]

Answer 11

Make certain you know the two forms of the equation of a parabola mentioned here:

1) "standard form" y=ax^2+bx+c

2) "vertex form" y-k=a(x-h)^2

Given the function f(x) = 2(x-3)(x+4), multiply out the product of the 2nd and 3rd factors. Write your result as y=2(x^2 - ? + ? ).

Now, "complete the square" for the quadratic inside parentheses.
Have you done "completing the square" before? If so, share what you remember of it.