Question

FAN AND MEDAL I PROMISE I JUST NEED HELP!!!!:)
Will attach picture.
I need to know the steps it takes to get to this answer. I am doing a presentation for math and i have to follow the steps it takes to get the correct answer. Thanks

Answer 1

May I help?

Answer 2

@macabbey101

Answer 3

@3mar please

Answer 4

What do you think?

Answer 5

Can you kindly respond more faster, please?

Answer 6

I know the answer is B but I don't know the steps it takes to get there. @3mar

Answer 7

Ok

Answer 8

How should you modify J^4 to let it do inside the square root?

Answer 9

(j^8)^1/2 is how you get j^4. i just really need to know how to get 98 to 7 because when I do (98)^1/2 that doesnt work, but it does with every other number.

Answer 10

Great! so you need to be more precise!

Answer 11

would it be (49)^1/2 =7?

Answer 12

i think i got it!! it would just be 98/2 before i put it in parenthesis

Answer 13

If you raise 7 to the power 2 and the * by 2 what you get?
\[7=(7^2)^{\frac{ 1 }{ 2 }}=\sqrt{7^2}.....\sqrt{2}*\sqrt{7^2}=\sqrt{2*7^2}=\sqrt{2*49}=\sqrt{98}\]

Answer 14

so i was right about 49?

Answer 15

Right!
7^2 then 2*7^2

Answer 16

thank you! can i @ you if i have any more questions?

Answer 17

@3mar

Answer 18

now?

Answer 19

You are so welcome!

Answer 20

No, just if I have more questions that Ineed help with in the next few minutes @3mar

Answer 21

Won't be late for any help.