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Mathematics 14 Online
OpenStudy (destinyyyy):

Elementary Statistics questions..

OpenStudy (dumbcow):

the sample proportion is always the midpoint in the confidence interval. ----> (.77+73)/2 = 0.75 The margin of error is the difference between the midpoint and the endpoints of confidence interval ---> 0.77 - 0.75 = 0.02

OpenStudy (destinyyyy):

Oh. So I completely ignore 95% confidence?

OpenStudy (destinyyyy):

I have a few more questions that I have no examples of, would you mind helping me with some of them?

OpenStudy (dumbcow):

sure, well the 95% confindence is important in setting up the interval but since its given to you, its not relevant to answering those questions

OpenStudy (destinyyyy):

Alright. Thank you

OpenStudy (destinyyyy):

I have no idea on where to even start on these

OpenStudy (dumbcow):

\[n = \frac{z^2 p(1-p)}{M^2}\] z = 1.96 because we want 95% confidence p = 0.5 M = margin of error = 0.02

OpenStudy (dumbcow):

by the way here is a reference i am using: https://onlinecourses.science.psu.edu/stat200/node/256

OpenStudy (destinyyyy):

I have never seen that formula before

OpenStudy (dumbcow):

what formulas are you using in class?

OpenStudy (destinyyyy):

OpenStudy (destinyyyy):

For these questions Im working under chapters 6 and 7

OpenStudy (dumbcow):

ok its same formula used for sample size in ch. 6 they use E for margin of error they use sigma for variance, for proportions \[\sigma^2 = p (1-p)\]

OpenStudy (dumbcow):

when they use q, q = 1-p

OpenStudy (destinyyyy):

Sorry but which formula are you talking about exactly?

OpenStudy (dumbcow):

Chapter 6: Min sample size to estimate p: \[n = pq (\frac{z}{E})^2\] q = 1-p z = 1.96 for 95% confidence E = 0.02

OpenStudy (destinyyyy):

Okay I thought so

OpenStudy (destinyyyy):

I got 2401

OpenStudy (dumbcow):

yes correct

OpenStudy (destinyyyy):

Okay. Next question

OpenStudy (destinyyyy):

Its a three part one :/

OpenStudy (dumbcow):

first lets find null hypothesis he picks up avg of 4 tons alternative would be picking up more than 4 tons \[H_0 : x = 4\] \[H_a: x > 4\]

OpenStudy (destinyyyy):

Hmm I don't have that an an option. A. Ho: >4 vs. Ha: <4 B. Ho: </ 4 vs, Ha: >4 C. Ho: >/ 4 vs Ha: <4 D. Ho: = 4 Ha: =/ 4

OpenStudy (destinyyyy):

The type II error is: Not concluding that the garbage collector picks up on average more than four tons of garbage per day when, in fact, he does.

OpenStudy (dumbcow):

oh ok, well null hypothesis is the normal default action. in this case it picking up 4 or less tons answer B

OpenStudy (destinyyyy):

Okay

OpenStudy (dumbcow):

type 2 error answer is right

OpenStudy (destinyyyy):

Alright

OpenStudy (dumbcow):

ok a = .05 p = .04 if p < a , what do we do?

OpenStudy (destinyyyy):

If p-value is less than alpha, the null hypothesis should be rejected

OpenStudy (dumbcow):

correct

OpenStudy (destinyyyy):

It was one of my previous questions

OpenStudy (destinyyyy):

My options are: A. Fail to reject Ho because the p-value is less than 0.05 B. Reject Ho because the p-value is less then 0.05 C. Accept Ho because the p-value is less than 0.05 D. Fail to accept Ho because the p-value is less than 0.05

OpenStudy (dumbcow):

B, you either reject or fail to reject

OpenStudy (destinyyyy):

Okay.. I have three more. Im going to put them in a new question so I can give you another metal. And this question is getting long.

OpenStudy (dumbcow):

ok

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