Question

Which one is it

Answer 1

You have to factor

Answer 2

Do you know how to do that?

Answer 3

NOPE

Answer 4

How do I?

Answer 5

\[2x^2 -7x - 4 = 0 \rightarrow (2x + 1)(x -4 ) = 0\]

Answer 6

so 4?

Answer 7

You divide the first parentheses by 2,

\[(x + \frac{ 1 }{ 2 })(x - 4) = 0\]

Answer 8

Take the opposite sign of each number

\[x = -\frac{ 1 }{ 2 } \]

\[x = 4\]

Answer 9

The reason that works, is because

\[(-\frac{ 1 }{ 2 } + \frac{ 1 }{ 2 })(4 - 4) = 0\]

\[(0)(0) = 0 \rightarrow 0 = 0\]

True

Answer 10

It said you were wrong

Answer 11

What did you input?

Answer 12

what x?

Answer 13

\[-\frac{ 1 }{ 2 }, 4\]

Answer 14

There are two solutions

Answer 15

I got to put both of them
OHHHHHHHhhHHHH

Answer 16

Yeah, it says "write both solutions, separated by a comma"

Answer 17

It all makes sense now thanks for the help

Answer 18

No problem