Question

5-3^x=-40 round to the nearest ten-thousandth
(gradpoint)

Answer 1

If you want to solve for x, we would proceed like that.

\[5-3^x=-40\]
\[5-3^x+40=-40+40\]
\[45-3^x=0\]
\[45-3^x+3^x=0+3^x\]
\[45=3^x\]

now you can take the log for both sides

\[\log(45)=\log(3^x)\]
\[\log(45)=xlog(3)\]
\[\frac{ \log(45) }{ \log(3) }=x\]
\[x=\frac{ \log45 }{ \log3 }=3.465\]


I hope I helped you.

Answer 2

thank you for showing the problem out like this

Answer 3

You are welcome!
Pleasure is mine!