Question

Seth is using the figure shown below to prove Pythagorean Theorem using triangle similarity:

In the given triangle ABC, angle A is 90o and segment AD is perpendicular to segment BC.

The figure shows triangle ABC with right angle at A and segment AD. Point D is on side BC.

Which of these could be a step to prove that BC2 = AB2 + AC2?

By the cross product property, AB2 = BC multiplied by BD.
By the cross product property, AC2 = BC multiplied by BD.
By the cross product property, AC2 = BC multiplied by AD.
By the cross product property, AB2 = BC multiplied by AD.

Answer 1

@Jaynator495

Answer 2

Is it B?

Answer 3

This is my last question by the way

Answer 4

Let me check.

Answer 5

Was there a image that went with this question?

Answer 6

http://prntscr.com/d2ox2c

Answer 7

Sorry forgot to post it

Answer 8

I assume that on the question it looks like \(\Large\sf AB^2\)?

Answer 9

Yes

Answer 10

Alright, just had to double check lol

Answer 11

\[BC^2=AB^2+AC^2\]

Answer 12

Well... This is pretty much the only area of geometry I have trouble with... ya...
I can't reliably help you in this problem, as I won't know for fact I'm correct, let me find someone who can however!

Answer 13

@Directrix he probably won't show, so i'll work on finding someone else...

Answer 14

@mathstudent55

Answer 15

@ganeshie8

Answer 16

I haven't been in the math section in so long, idk who helps anymore LOL

Answer 17

I only know the older helpers x'D

Answer 18

Darn it

Answer 19

Don;'t try anymore because I just submitted the assignment and I got a 40% on it

Answer 20

aww

Answer 21

I was trying the problem out .-.

Answer 22

I'm fixing to cry right now but every one of the ones that @Jaynator495 Helped me with I got right

Answer 23

the cross product property would use the idea that BC multiplied by AD is the area of the triangle

Answer 24

I spent hours on this assignment for nothing

Answer 25

I'm sorry! ;-;

At least you got the last one right ;-;