Question

Use synthetic substitution to evaluate P(x) = x^3 + 3x^2 - 6 for x = -1.

P(-1) = ____ Enter a number only.

Answer 1

need some help

Answer 2

quite a bit

Answer 3

or nah

Answer 4

yeah im kinda dying here

Answer 5

what you mean?

Answer 6

im dying i need help

Answer 7

okay

Answer 8

hey @ahsan are you new here

Answer 9

here If one root is -3, the remainder will be zero when the polynomial is divided by (x+3). Using synthetic division, we can evaluate the remainder easily.
.. 2, -3, p, 30 ... first row of synthetic division is the coefficients of the polynomial
.. - , -6, 27, (-3p-81) ... result of multiplying the bottom row by -3
.. 2, -9, (p+27), (-3p-51) ... bottom row is the sum of the first two rows.

In order for the remainder to be zero, the value of (-3p-51) must be zero.
.. -3p - 51 = 0
.. -3p = 51
.. p = 51/-3 = -17

The coefficients of the polynomial resulting from division by (x+2) are {2, -9, -17+27}, so the original polynomial factors as
.. (x+3)(2x^2-9x+10) = 0
.. (x+3)(2x-5)(x-2) = 0 ... factoring the quadratic

The value of p is -17, and the other roots are 2.5 and 2.

Answer 10

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Answer 11

wut

Answer 12

huh?

Answer 13

i dont get it

Answer 14

okay