I really need some help! Triangle PQR is transformed to triangle P'Q'R'. Triangle PQR has vertices P(8, 0), Q(6, 2), and R(−2, −4). Triangle P'Q'R' has vertices P'(4, 0), Q'(3, 1), and R'(−1, −2). Plot triangles PQR and P'Q'R' on your own coordinate grid. Part A: What is the scale factor of the dilation that transforms triangle PQR to triangle P'Q'R'? Explain your answer. (4 points) Part B: Write the coordinates of triangle P"Q"R" obtained after P'Q'R' is reflected about the y-axis. (4 points) Part C: Are the two triangles PQR and P''Q''R'' congruent? Explain your answer. (2 points) @3mar
Well, I am here.
Can you plot them, please?
im not vary good at this. I really don't know what to do.
This question didn't even come with a pic.
I am on it. It is easy In Sha' Allah
Take that, please! I hope that helps!
Is this right? I think so. If you multiply 8 by 0.25 (or 1/4) you get 2. The sides of the new triangle are 1/4 the size of the sides of the original triangle.
I don't think so. It is not calculated like that. How did you know that "ultiply 8 by 0.25 (or 1/4) you get 2"??? "The sides of the new triangle are 1/4 the size of the sides of the original triangle"?? Where are the steps for that?
....I have no idea some kid next to me is doing the same question ant that's what he said he has. I wasn't really looking at his math, I just wanted to see if that was right or not I I gusset its wrong.
I really don't know how to do most of this.
Step by step. Can you calculate the distance of any side of the original triangle for me, please? Use this formula!
@naruko885
Im sorry I have no idea..... :(
You are in grade #? if I may know?
Im in 8th but I should be in 10th but I have dyslexia with number to the extreme. Im in all advanced honors classes, only math im not in advanced and I have a 5o4 plane for it meaning I get extra help with it but the person that helps me isn't hear today.
I have been held back grades for my math skills sadly.......
To get the distance of side (8,0) and (-2,-4): \[length=\sqrt{((8-(-2))^2+(0-(-4))^2}=\sqrt{100+16}=2\sqrt{29}\] ok until here!?
Can you kindly respond more faster, please?
To get the distance of side (4,0) and (-1,-2) of the transformed triangle: \[length=\sqrt{(4-(-1))^2+(0-(-2))^2}=\sqrt{25+4}=\sqrt{29}\]
Give me 5 min please!
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