Question

help with this plz

Answer 1

Thank you for giving me a neck exercise :p

Answer 2

sorrrry :(

Answer 3

im having neck and shoulder pain 4 hrs on this hw

Answer 4

O.o 4 hours on math hw? Why though.

Answer 5

idk math is confusing. n these 2 r the last questions thats it. n them I am done and so will you be

Answer 6

I think the "neck exercise" means I have to lean the head to read your problem. hahaha... and I can't stay long on that style.

Answer 7

ik . n SWEAR this is the last pg 2 more questions THATS IT

Answer 8

Is it not that \(S'(t) = 3f'(x)= 3\) at x = 2??

Answer 9

Yes

Answer 10

But it says velocity soooooooo I'm lost

Answer 11

Derivative of position is the velocity.

Answer 12

oh!! I supposed you know that!! :)

Answer 13

so would it be (C) 1

Answer 14

@Loser66 @steve816

Answer 15

or d 3

Answer 16

@sshayer @3mar

Answer 17

4 or 5?

Answer 18

both plz

Answer 19

If you are given the position as a function, so its first derivative is the velocity of the particle and the second represents its acceleration.

ok?

Answer 20

@steve816 yup, hurt my neck too. Then i saw the number of answering posts

Answer 21

@khantahmina

Do you follow?

Answer 22

yes i got it. m computer is acting up sorry

Answer 23

so s(t)= 3f(x)+1
so derivatve of that is 3

Answer 24

proceed?

Answer 25

yes lets move onto 5.

Answer 26

no for 4 it is already listed it table..
x=2 >>>>> pick 1 at f'(x)

got that?

Answer 27

im saying none of these because as x approaches 1 from the negative side it does not exist and which is not equal to as x approaches 1 from the postive side

Answer 28

AND yes i got what you said i was a little confused on should i use the formula or not

Answer 29

the formula for 5 and the table for 4
ok?

Answer 30

ok

Answer 31

so 4 is done or what?

Answer 32

done

Answer 33

we shall proceed

Answer 34

What do you think about 5?

Answer 35

I am busy.
I have less than 10 min to go!

Answer 36

@khantahmina

Let me know where you are back!