Question

What value of k makes the equation true?
(5a²b³)(6a^k(b))=30a^6(b^4)

A)2
B)3
C)4
D)8

Answer 1

there are

(5a^2b^3)(6a^(k) *b) = 30a^6 *b^4

30a^(2k) *b^4 = 30a^6 *b^4

2k = 6

k = ?

Answer 2

do you understand me ?

Answer 3

@cam1258 do you have question about above wrote ?

Answer 4

I know it is not A or D

Answer 5

Is that correct?

Answer 6

If 2k=6, k=3...

Answer 7

so than you see there above wrote that

2k = 6 divide both sides by 2

k = 6/2 = ?

Answer 8

B

Answer 9

@cam1258 do you understand the way how you get the right answer ?

Answer 10

Yes, I do. Thank you for explaining and helping

Answer 11

yw

my pleasure and anytime

good luck

bye bye

Answer 12

\((5a^2b^3)(6a^k(b))=30a^6(b^4)\)

\(5 \times a^2 \times b^3 \times 6 \times a^k \times b=30 \times a^6 \times b^4\)

\(5 \times 6 \times a^2 \times a^k \times b^3 \times b=30 \times a^6 \times b^4\)

\((5 \times 6) \times (a^2 \times a^k) \times (b^3 \times b)=30 \times a^6 \times b^4\)

\(30 \times a^{2+k} \times b^4 = 30 \times a^6 \times b^4\)

\(\cancel{30} \times a^{2+k} \times \cancel{b^4} = \cancel{30} \times a^6 \times \cancel{b^4}\)

\(a^{2+k} = a^6\)

\(2 + k = 6\)

\(k = 4\)

Answer 13

@jhonyy9

\(\Large a^2 \times a^k = a^{2 + k} \ne a^{2k} \)

Answer 14

Answer is not B.

Answer 15

ohhh - yes ! sorry - but the way is to start like above i started it

so this mean that a^(2+k) = a^6 so 2+k=6 => k = 6-2 so k=4 and in this way the choice C. is right sure

thank you very very much @mathstudent55