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Mathematics 49 Online
OpenStudy (jakob):

@Jamierox4ev3r @MaddieLB

OpenStudy (jakob):

OpenStudy (maddielb):

Im trying, gimme a min

OpenStudy (jakob):

K :)

OpenStudy (maddielb):

Yeah I dont know

OpenStudy (jakob):

*Facepalm Your graduating right?

OpenStudy (maddielb):

Wait a second, lemme try this

OpenStudy (maddielb):

Yeah I'm dumb :) Sorry

OpenStudy (5sos):

I got you. It's fine Maddie!<3

OpenStudy (maddielb):

Lol

OpenStudy (5sos):

So from 1990->1999 it went up 3 million. So that tell us that every 9 years the population increases by 3 million people.

OpenStudy (jakob):

Yeah

OpenStudy (5sos):

And from 1999 to 2016 is how many years?

OpenStudy (jakob):

this many

OpenStudy (jakob):

no 17

OpenStudy (5sos):

Correct. So you divide 17 by 3 then times by 3. Again. Understand where I got the numbers from?

OpenStudy (jakob):

Yeah

OpenStudy (5sos):

SO your answer needs to be rounded. Do you know how to round?

OpenStudy (jakob):

yeah so 20?

OpenStudy (jakob):

idk I know how to round

HanAkoSolo (jamierox4ev3r):

@5sos are you using the exponential growth formula? Because @Jakob should be solving for k, which is the growth constant. Then he can use this number to solve for the estimate of 2016.

OpenStudy (5sos):

I'm trying to help as best as possible.

HanAkoSolo (jamierox4ev3r):

I'm sure you are :) I'm just here to serve as quality control, that is all :) I'm thinking that you're looking at this problem very simplistically, which I like, but I fear that there are more steps involved.

OpenStudy (5sos):

Then Can you help him solve it since I'm having trouble?

HanAkoSolo (jamierox4ev3r):

Sure. So first off, we want to use the formula to find our k, which is the rate of decay.

OpenStudy (jakob):

K

HanAkoSolo (jamierox4ev3r):

We are given \(P=Ae^{kt}\) So if P=40,000,000, A = 37,000,000, and t=9 (because 9 years passed since we saw the changes in population), can you plug that into the equation? @Jakob

HanAkoSolo (jamierox4ev3r):

haha, I know we can. I was wondering if you'd like to try your hand at putting it in the equation :P @Jakob

OpenStudy (jakob):

40,000,000=37,000,000e^k9

HanAkoSolo (jamierox4ev3r):

yup! Somewhat gross looking, isn't it? It could be rewritten as \(40,000,000=37,000,000e^{9k}\) , just to make it look nicer

HanAkoSolo (jamierox4ev3r):

So once we have this, we have to solve for k. Can you do that, or would you like me to help you?

OpenStudy (jakob):

Yeah help please

HanAkoSolo (jamierox4ev3r):

So you can divide both sides by 37,000,000 in order to get \(e^{9k}\) by itself. So that would look something like this: \(40,000,000=37,000,000e^{9k}\) /37,000,000 /37,000,000 -------------------------- 1.081=\(e^{9k}\)

HanAkoSolo (jamierox4ev3r):

Do you see how I got there?

OpenStudy (jakob):

Yeah

HanAkoSolo (jamierox4ev3r):

Okay, good. from here, we take some thing called the "natural logarithm" of both sides. Do you know what I'm talking about?

OpenStudy (jakob):

Ehhh

HanAkoSolo (jamierox4ev3r):

I'm assuming that's a no? XD My God..I'm so sorry

OpenStudy (jakob):

Its fine school lets out in 35 mins Can you see why I asked for a direct answer?

OpenStudy (jakob):

And not only do we have to finish this but 9 more after

HanAkoSolo (jamierox4ev3r):

rip. I understand. I just want to abide by site guidelines. I'm hoping you are able to learn from what I am doing here.

OpenStudy (jakob):

Not really just like everything Now school is so hard its like it goes on one ear and out thee other

OpenStudy (jakob):

But I am learning but tomarrow I will be clueless

HanAkoSolo (jamierox4ev3r):

Yep, I get that. Okay. well...I have to go soon, so I'll just finish walking you through this particular problem. Hopefully the rest will make more sense.

HanAkoSolo (jamierox4ev3r):

So a basic rule that you should know starting now is that \[\ln(e)=1\]

HanAkoSolo (jamierox4ev3r):

So by taking the natural logarithm of both sides (ln), you are left with the following 1.081=\(e^{9k}\) ln(1.081)=9k

HanAkoSolo (jamierox4ev3r):

at this point, solve for ln(1.081) on your calculator, then divide that answer by 9. That is your k.

OpenStudy (jakob):

yeah I am lost now

HanAkoSolo (jamierox4ev3r):

You got me up to 1.081=\(e^{9k}\), correct?

OpenStudy (jakob):

yeah

HanAkoSolo (jamierox4ev3r):

taking the ln of each side is not too difficult. You should have a button on your calculator that will help you calculate ln (1.081)

OpenStudy (jakob):

But I dont

OpenStudy (jakob):

Its fine just go on I will try someway to find this and learn

HanAkoSolo (jamierox4ev3r):

. . .I always used the ln button to solve these problems. My God, I apologize...

OpenStudy (jakob):

Its fine My school is very strict they want you do do everything on your own.... I am surprised This isn't blocked

HanAkoSolo (jamierox4ev3r):

I see.

OpenStudy (jakob):

Alright well have a good day

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