@Jamierox4ev3r @MaddieLB
Im trying, gimme a min
K :)
Yeah I dont know
*Facepalm Your graduating right?
Wait a second, lemme try this
Yeah I'm dumb :) Sorry
I got you. It's fine Maddie!<3
Lol
So from 1990->1999 it went up 3 million. So that tell us that every 9 years the population increases by 3 million people.
Yeah
And from 1999 to 2016 is how many years?
this many
no 17
Correct. So you divide 17 by 3 then times by 3. Again. Understand where I got the numbers from?
Yeah
SO your answer needs to be rounded. Do you know how to round?
yeah so 20?
idk I know how to round
@5sos are you using the exponential growth formula? Because @Jakob should be solving for k, which is the growth constant. Then he can use this number to solve for the estimate of 2016.
I'm trying to help as best as possible.
I'm sure you are :) I'm just here to serve as quality control, that is all :) I'm thinking that you're looking at this problem very simplistically, which I like, but I fear that there are more steps involved.
Then Can you help him solve it since I'm having trouble?
Sure. So first off, we want to use the formula to find our k, which is the rate of decay.
K
We are given \(P=Ae^{kt}\) So if P=40,000,000, A = 37,000,000, and t=9 (because 9 years passed since we saw the changes in population), can you plug that into the equation? @Jakob
haha, I know we can. I was wondering if you'd like to try your hand at putting it in the equation :P @Jakob
40,000,000=37,000,000e^k9
yup! Somewhat gross looking, isn't it? It could be rewritten as \(40,000,000=37,000,000e^{9k}\) , just to make it look nicer
So once we have this, we have to solve for k. Can you do that, or would you like me to help you?
Yeah help please
So you can divide both sides by 37,000,000 in order to get \(e^{9k}\) by itself. So that would look something like this: \(40,000,000=37,000,000e^{9k}\) /37,000,000 /37,000,000 -------------------------- 1.081=\(e^{9k}\)
Do you see how I got there?
Yeah
Okay, good. from here, we take some thing called the "natural logarithm" of both sides. Do you know what I'm talking about?
Ehhh
I'm assuming that's a no? XD My God..I'm so sorry
Its fine school lets out in 35 mins Can you see why I asked for a direct answer?
And not only do we have to finish this but 9 more after
rip. I understand. I just want to abide by site guidelines. I'm hoping you are able to learn from what I am doing here.
Not really just like everything Now school is so hard its like it goes on one ear and out thee other
But I am learning but tomarrow I will be clueless
Yep, I get that. Okay. well...I have to go soon, so I'll just finish walking you through this particular problem. Hopefully the rest will make more sense.
So a basic rule that you should know starting now is that \[\ln(e)=1\]
So by taking the natural logarithm of both sides (ln), you are left with the following 1.081=\(e^{9k}\) ln(1.081)=9k
at this point, solve for ln(1.081) on your calculator, then divide that answer by 9. That is your k.
yeah I am lost now
You got me up to 1.081=\(e^{9k}\), correct?
yeah
taking the ln of each side is not too difficult. You should have a button on your calculator that will help you calculate ln (1.081)
But I dont
Its fine just go on I will try someway to find this and learn
. . .I always used the ln button to solve these problems. My God, I apologize...
Its fine My school is very strict they want you do do everything on your own.... I am surprised This isn't blocked
I see.
Alright well have a good day
Join our real-time social learning platform and learn together with your friends!