Kraken and seven other pirates agreed to share a pile of gold pieces equally. Right before they divided up the gold, two more pirates showed up and demanded to be included, so the gold ended up getting divided among ten pirates instead. Kraken received 40 fewer pieces of gold than he would have if the two extra pirates hadn't arrived. How many pieces of gold did Kraken receive?
Okay, so what would YOU do first? I would make two equations.
@Filllip66 It's true that you may need to make two equations for this problem.
you do 8a=10b and b=a-40
Make one equation where x is the pieces of gold that is to be divided equally and y is the number of pieces that Kraken would receive if there were only 8 pirates. Make the second equation with the same x and y variables but now if there were only 10 pirates.
So I got the answer a=200
But I need B
What does a and b mean?
You need to properly declare your variables.
Oh I got the answer
Thank you
It equals 160
Thank you
Those are the pieces of gold that Kraken if there were 8 and 10 pirates. But what is the original number of pieces to be divided equally?
160
Incorrect.
If not 200
I think
That is also incorrect.
I am pretty sure that you are very close to the actual answer.
Hmmmm.............
DO NOT KNOW
Here are my equations: \(x\) = pieces of gold to be divided \(y\) = pieces of gold that Kraken will receive with 10 pirates for 8 pirates... \[\frac{x}{8} = 40 + y\] for 10 pirates... \[\frac{x}{10} = y\]
Do you understand how I came about writing my equations?
Yes
Now use elimination or substitution (although I prefer the latter method) to solve for the value of \(x\).
Dont get it
Are you stuck with solving for x?
I WAS RIGHT
What do you mean?
I CHECKED AND GOT IT
But still thank you
Shoot! I did not understand the directions very clearly. Very sorry :(
Hey
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