Question

Chau's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Chau
$5.70
per pound, and type B coffee costs
$4.35
per pound. This month, Chau made
179
pounds of the blend, for a total cost of
$886.65. How many pounds of type B coffee did he use?

Answer 1

@Will.H

Answer 2

for coffee A = 5.70/lb
for coffee B = 4.35/lb

x = # of lb for coffee A
y = # of lb for coffee B

x(5.70) + y(4.35) = 886.65

We also know that combine pounds for both coffee A and B is 179
x + y = 179

--------
Now just solve for x for the first equation and substitute that value to 2nd equation.
Afterward, just solve for y and that's the value for how many pounds for coffeeB.

Answer 3

i got 120

Answer 4

Let me check:

x(5.70) + y(4.35) = 886.65
5.70x = 886.65 -4.35y
x = (886.65-4.35)/5.70

now substitute that x value into equation #2:

(886.65-4.35y)/5.70 + y = 179

http://www.wolframalpha.com/input/?i=(886.65+-4.35y)%2F5.70++%2B+y+%3D+179

y = 99

Answer 5

You can double check the work:
99 * 4.35 = 430.65
88 * 5.7 =456

so,
430.65 + 456 ===> 886.65

Answer 6

Edit, 88 is actually 80

Answer 7

so it would be 80 pounds?

Answer 8

No, you want value for coffee B, so it's value for y

y= 99

Answer 9

@Will.H would it be 66 pounds then?

Answer 10

@Ebonyserrano , refer to previous posts
You want type B which is represented by "y"

... y = 99