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Mathematics 8 Online
OpenStudy (leenathan):

helpppppp plz

OpenStudy (leenathan):

http://prntscr.com/deittm

OpenStudy (mecharv):

Hey, do you know Pythagoras theorem?

OpenStudy (leenathan):

yus i think the answer is B

OpenStudy (mecharv):

|dw:1480695288154:dw| here, \[(AC)^2=(AB)^2+(BC)^2\]

OpenStudy (mecharv):

How did you come up with B?

OpenStudy (kaithang):

\[a ^{2 } + b ^{2} = c ^{2}\]

OpenStudy (kaithang):

Therefore 2 + ? = 4

OpenStudy (leenathan):

i asked my friend im trying to solve it now tho

OpenStudy (leenathan):

2+(2)=4

OpenStudy (leenathan):

oh so a

OpenStudy (mecharv):

It is given \[AC=4units \]\[BC/AB=2units\]

OpenStudy (kaithang):

Idk if that is right but I' think it is

OpenStudy (mecharv):

So, \[4^2=2^2+(AB)^2\]

OpenStudy (leenathan):

hmmm i think its right but i want to make sure its correct

OpenStudy (mecharv):

\[16=4+(AB)^2\] So now can you figure out what AB must be?

OpenStudy (leenathan):

http://prntscr.com/dej0lu i found an example

OpenStudy (kaithang):

OMg that makes since @mecharv I prolly confused the heck out of @leenathan

OpenStudy (leenathan):

wat?

OpenStudy (mecharv):

@kaithang that is okay :) You too got to learn something. Now @leenathan what is the answer?

OpenStudy (leenathan):

a

OpenStudy (mecharv):

No. How is it a? I have almost given you the answer....

OpenStudy (leenathan):

@mecharv 12?

OpenStudy (leenathan):

A^2 + B^2 = C^2 we have A = 2 and C = 4 we need to find B 2^2 + B^2 = 4^2 4 + B^2 = 16 B^2 = 12 B = sqrt12

OpenStudy (leenathan):

c

OpenStudy (mecharv):

Yes that is correct :) Always work out your problems mate. Cheers :)

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