Question

What is the equation for the graph shown? Will add a picture of the graphs in a comment. Help is EXTREMELY appreciated, trig is hard!

Answer 1

Can you identify the basic trig function showin in Problems 28 and 29?

Answer 2

@mathmale sorry the late response! It's a cot function right?

Answer 3

Surely looks like the graph of the tangent funciton to me. double-check.
What is the period of this function?

Answer 4

pi?

Answer 5

Two graphs are given. Which graph are you referring to? In one case the period is pi; in the other case the period is 2pi.

When writing this trig function, what would you suppose would be an appropriate amplitude?

Answer 6

@mathmale So with the first graph, the period is pi. Is the amplitude 3?

Answer 7

Or wait, there's no amplitude!

Answer 8

@mathmale

Answer 9

@johnweldon1993 Help!

Answer 10

For now, let's just say the amplitude is 1. It's incorrect to say that "there's no amplitude." If there really were no amplitude value, there'd be no graph.

Yes, in the first problem, the period is pi. Assume that the amplitude is 1.

Last job is to determine the phase shift. Are you aware that the basic tangent function always goes through (0,0)? Try to determine how far the entire graph has been shifted to the right to appear as it does.

Answer 11

Yes, tangent goes through (0,0) and cotangent does not. So it was moved over 6pi?

Answer 12

@pooja195

Answer 13

@mathmale

Answer 14

@pooja195 @triciaal Please someone help me. These are the last two questions, I need help understanding.

Answer 15

@3mar Please help me

Answer 16

@legomyego180 Can you help me?

Answer 17

@likeabossssssss Can you help me?

Answer 18

Well, I am here.
Any Help... Any Time...

How could I help you?

Answer 19

Ah thank God, I'll repost the two graphs.

Answer 20

I need to write out the equations for both graphs, but I need some help.

Answer 21

I am with you, don't worry!

Answer 22

Awesome, so I thought cotangent graphs didn't go through (0,0), and that it was only tangent graphs. Is this true?

Answer 23

Could you give me 2 min, please?
Just to check it with pen and paper

Answer 24

Of course!!

Answer 25

Thank you.

Answer 26

First of all, these are trigonometric functions!
right?

Answer 27

Yes!

Answer 28

Great!
And also they are the tangent functions!
right?

Answer 29

I thought tagent functions went through (0,0) and these don't?

Answer 30

Yes, I mean BASICALLY it is tan(x), with some shifting or stretching!
agree?
http://www.biology.arizona.edu/biomath/tutorials/trigonometric/graphics/trig_tan.gif

Answer 31

Ah alright, yes I agree!

Answer 32

So now...
y=tan(x)
passes through the origin and confined between \(\pi/2~ and ~-\pi/2\)

Answer 33

Yes, and the period is pi.

Answer 34

Right?

Answer 35

Right!
so what about this and question 28?
Is there any common thing?
https://www.desmos.com/calculator/sbsqjj5xnu

Answer 36

Well the period in the link you sent me 2pi correct?

Answer 37

Is the amplitude 1?

Answer 38

No, it is π

Answer 39

Oh alright

Answer 40

so the answer is for 28 is ?

Answer 41

y=tan2pi?

Answer 42

you mean: \(y=tan(x)\)??

Answer 43

Yes... So that's the equation?

Answer 44

I just ask you to make sure you got the idea or not!

Answer 45

Oh yes haha :)

Answer 46

so Are you persuaded for the first question?

Answer 47

I still don't understand how to find the function the first graph. :/

Answer 48

Ok, look again and tell me: what is the period?

Answer 49

the period is pi

Answer 50

@3mar

Answer 51

That is very good!

SO why is it not \(y=tan(x)\)??
https://www.desmos.com/calculator/ho1ksymqr8

Answer 52

Because y=tan(x) does not match the graph. Still needs the period put in?

Answer 53

Check the graph I sent you, it is the same!

Answer 54

Ah I see, so number 28 is just y=tan(x)?

Answer 55

And 29 is y=tan(1/2x) @3mar

Answer 56

28 is good for you firstly?

Answer 57

Yes

Answer 58

I am happy to hear that.

Answer 59

It would better to start your question in another new post if you don't mind!

Answer 60

Alright, well I think I got number 29. Thank you for your help!

Answer 61

Really??
This very good!

I just said that as the rules of this site: "One question per one post, please."

Answer 62

@3mar Gotcha. :)

Answer 63

Thank you for understanding!