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Question

mtalhahassan2 · Answer

in this question i believe they want us to solve for n right?

mtalhahassan2 · Answer

400mSv/hr=4msv/hr/ 10^n

mtalhahassan2 · Answer

i didn't get that 15?

mtalhahassan2 · Answer

Thickness of a shielding material that reduces intensity to 1/10th of its initial value?

sunnnystrong · Answer

Okay so:
Recall that
$$I2=\frac{ I1 }{ 10^n }$$
$$n=Shell thickness/TVL$$

mtalhahassan2 · Answer

ok

sunnnystrong · Answer

$$4mSv/hr=\frac{ 400mSv/hr }{ 10^{(x/15)} }$$
Solve for x

mtalhahassan2 · Answer

so we can do the cross multiply

sunnnystrong · Answer

Bunch of math basicallly lol yes

sunnnystrong · Answer

$$40^{\frac{ x }{ 15 }}=400$$
$$ln(40^{\frac{ x }{ 15 }})=ln(400)$$
$$\frac{ x }{ 15 }\ln(40)=\ln(400)$$
Solve for x:

so
x=24.362 cm

mtalhahassan2 · Answer

ok let me check if i am getting the same answer

sunnnystrong · Answer

okay sounds good (: sorry for late replies these are actually hard haha

mtalhahassan2 · Answer

lol that's ok i know its hard but thanks a lot today you helped me a lot really appreciated :))

sunnnystrong · Answer

NP I am always happy to help! These are interesting questions
For what class is this for?

mtalhahassan2 · Answer

finally i got the same answer and it is for my health and safety class..

sunnnystrong · Answer

Wow that's crazy lol XD

mtalhahassan2 · Answer

yea I know LOL