Question

help plz

Answer 1

http://prntscr.com/djtlnj

Answer 2

Please consider exponent rules. Multiply all the inside exponents by that "-2".

Answer 3

wait let me write it out

Answer 4

\[(\frac{ xy^3 }{ x^-4y^4 }) ^-2\]

Answer 5

\[xy^3 \]*\[^-2\]

Answer 6

Okay, that's what we already saw. Now, use the exponent rules.

Answer 7

3*-2 right?

Answer 8

or 3+-2

Answer 9

I'll do the numerator
\(\left(xy^{3}\right)^{-2} = x^{1\cdot (-2)}y^{3\cdot (-2)} = x^{-2}y^{-6}\)

Multiply each interior exponent by that exterior exponent.

You do the denominator.

Answer 10

OK SO \[X^-4 *-2\]=8 then \[y^4*-2\]=-8

Answer 11

right?

Answer 12

Try again, (-4)*(-2) = +8

Answer 13

ohhhhh ops

Answer 14

i forgot the - part

Answer 15

Still "A", though.

Notice B and D. If we multiply everything by -2, EVERY exponent must be a multiple of 2. You can throw out B and D immediately.

Answer 16

thanks can you help me on another?

Answer 17

Sure. Start a new thread, please. Close this one.