Question

help please

Answer 1

let's start by circling each outcome where at least one of the dice is 4

Answer 2

so you would just circle every number in column 4 and row 4

Answer 3

then cross out all outcomes that are > 5

Answer 4

that's it for part I

Answer 5

so when crossing it out I basically corss out all of the number I circles except for the 5's

Answer 6

right (but also include all sums greater than 5, not just the ones circled)

Answer 7

okay =)

Answer 8

the total numbers of 4 is 12 right for the next question

Answer 9

make sure to count each circled number only once

Answer 10

ohh I only count 8 once?

Answer 11

ohh I only count 8 once?

Answer 12

yes

Answer 13

oh okay that's where I screwed up

Answer 14

so it's just 11/36 for the first one

Answer 15

for Part B: number of crossed out numbers/36

Answer 16

26/36

Answer 17

13/18

Answer 18

good

Answer 19

for Part C, multiply your answers from part A and B ("and" in probability means multiply)

Answer 20

(11/36)(13/18) =

leave it as a fraction

Answer 21

143/648

Answer 22

good

Answer 23

part D you would just add the answers from part B and A (11/36 + 13/18) = ?

Answer 24

in probability, "or" means add

Answer 25

1 1/36

Answer 26

or 37

Answer 27

37/36

Answer 28

oh hold on, i missed something

Answer 29

you would then take 37, then subtract the numbers that are BOTH crossed out and circled

Answer 30

I count 9, so it would be (37-9)/36

Answer 31

28/36

Answer 32

basically, the formula is

(number of outcomes involving 4 on a die) + (number of outcomes greater than 5) - (number of outcomes that satistfy both these criteria)

Answer 33

so yes, 28/36 or 7/9