Question

help voc

Answer 1

@Vocaloid

Answer 2

https://s1.postimg.org/9iadrowlrj/Capture.png

Answer 3

yay help

Answer 4

do you understand how synthetic division works?

Answer 5

kind of

Answer 6

for problem 1, start by writing the coefficients of the polynomial

Answer 7

1 -12 54 -108 81

Answer 8

1 -3 -1 3

Answer 9

then put these into a synthetic division symbol

Answer 10

only one at a time please

Answer 11

so like question number 2

Answer 12

bring the first coefficient down

Answer 13

then multiply across this direction

Answer 14

it's not a factor

Answer 15

then we add down the column and keep repeating the process

Answer 16

do you think you can try the rest of it?

Answer 17

it's c and d

Answer 18

right?

Answer 19

I haven't finished the calculations yet

Answer 20

yeah I get c and d too

Answer 21

2nd one

Answer 22

I noticed in the third column they tried to multiply 1*1 to get 2? so I believe that's where the error is

Answer 23

so line 2

Answer 24

anyway, for the last one, let me check your calculations

Answer 25

ok

Answer 26

yes, your answer is correct

Answer 27

i'll have a few more of i can't figure them out

Answer 28

ok, go for it

Answer 29

https://s1.postimg.org/64hupa5cgf/Capture.png

Answer 30

complex root theorem: if a + bi is a root then a - bi is a root

Answer 31

so if -3 + 2i is a root, what must also be a root?

Answer 32

c

Answer 33

yup good

Answer 34

for 2 you would just have to do synthetic division with all of the roots (sorry)

Answer 35

oh wait I just realized that some of the roots are complex hmm

Answer 36

a?

Answer 37

well this is embarrassing I don't remember how to find complex roots for non-quadratic equations

Answer 38

my best bet would be to plug in the complex root and see which one gives you 0 as the result

Answer 39

sorry ;;

Answer 40

I know the answer is either a or b based on -4 not being a root

Answer 41

i got all my answers correct

Answer 42

oh awesome! good job

Answer 43

I'm really rusty on this stuff ;_;

Answer 44

wanna help me on a little more if i need it

Answer 45

maybe not today, I need a break ;;

I think sillybilly should be able to assist though

Answer 46

https://s1.postimg.org/8li4g6vfkv/Capture.png

Answer 47

@sillybilly123

Answer 48

you only need to look at the lead terms. right?

Answer 49

cos you're putting unbelievably large numbers into a function.

Answer 50

just tot figure out end behavior yes

Answer 51

or you could graph it

Answer 52

why bother?

Answer 53

imagine in your head that you are looking at those functions, you realise that it is only really the leading term that matters for big numbers,...., and the let x = 10. hardly a big number, but you are starting to move away from the y-axis

Answer 54

b and d look wrong a?

Answer 55

well the ones with leading exponents that are even should give rise to even functions. options #3 and # 4. symmetrical.

Answer 56

then c

Answer 57

i'd look at a) and b) if i were you

Answer 58

there is only one answer

Answer 59

OMG, c) has \(x^6\) as the leading term. So it gets really big as \(x\) gets really big. but it is always going to be +ve, right?!?!

Answer 60

The answer is a) because as x gets really large you only really need to compute the first term: \(y = 7 x^9\). That function goes to \(+\infty\) as \(x \to +\infty\) and vice versa

Answer 61

i knew i was right

Answer 62

help on more?

Answer 63

when you say ""i knew i was right", did you mean that?!

Answer 64

not completely i knew b and d were wrong

Answer 65

k

one more

new thread though