Question

Which expression is equivalent to (3r/s)^3(s^2/9)
A~ r^3/s
B~ 3r^3/s
C~ 3r^3s
D~ r^3s

Answer 1

Does it look like this
\(\bf (\dfrac{3r}{s})^3(\dfrac{s^2}{9})\)

Answer 2

Yep

Answer 3

Ok so let's apply the ^3
\((3r)^3=27r^3\)
and \(s^3\)
\(\bf\dfrac{27r^3}{s^3}\)

Answer 4

\(\bf (\dfrac{27r^3}{s^3})(\dfrac{s^2}{9})\)
You can cross out s^2 from both s's which leaves you with \(\bf \dfrac{27r^3}{s}~and~\dfrac{1}{9}\) and then you can divide \(\bf 27r^3~and~9~by~3\)
Which basically leaves you with \(\bf \dfrac{3r^3}{s}*\dfrac{1}{1}=\dfrac{3r^3}{s}\)

Option B)

Answer 5

Thank you O: ♥

Answer 6

No problem :)