Question

please help

Answer 1

What is the equation of a line that is perpendicular to −x+3y=9 and passes through the point (−3, 2) ?

Answer 2

@PandaSurvive How do you think we should go about solving for this question?

Answer 3

I got up to the part where I had -x+3y=9 in slope intercept form but i cant remember what to do after that

Answer 4

Well you are correct in your first step. In order to solve for this question, we need the slope that is perpendicular to −x+3y=9

So we put it in terms of y, or slope intercept form

\[−x+3y=9 \]
\[3y = x + 9\]
\[y = \frac{ 1 }{ 3 }x + 3\]

The slope perpendicular to y = 1/3x + 3 is -3

Answer 5

Next, does this formula look familiar?

\[y - y _{1} = m(x - x _{1})\]

Answer 6

yes

Answer 7

How do we use it?

Answer 8

um

Answer 9

ohhhh

Answer 10

y-2= (x-(-3))

Answer 11

Good

Answer 12

Just remember to add in our slope :)

Answer 13

1/3

Answer 14

Our perpendicular slope .-.

Answer 15

oh -3 x'D

Answer 16

Haha xD

Answer 17

i got y=-3x-7

Answer 18

Correct, good job )

Answer 19

lol, botched smile .-.

Answer 20

thanks cx

Answer 21

haha no problem xD