PandaSurvive:

please help

6 days ago
PandaSurvive:

What is the equation of a line that is perpendicular to −x+3y=9 and passes through the point (−3, 2) ?

6 days ago
Shadow:

@PandaSurvive How do you think we should go about solving for this question?

6 days ago
PandaSurvive:

I got up to the part where I had -x+3y=9 in slope intercept form but i cant remember what to do after that

6 days ago
Shadow:

Well you are correct in your first step. In order to solve for this question, we need the slope that is perpendicular to −x+3y=9 So we put it in terms of y, or slope intercept form \[−x+3y=9 \] \[3y = x + 9\] \[y = \frac{ 1 }{ 3 }x + 3\] The slope perpendicular to y = 1/3x + 3 is -3

6 days ago
Shadow:

Next, does this formula look familiar? \[y - y _{1} = m(x - x _{1})\]

6 days ago
PandaSurvive:

yes

6 days ago
Shadow:

How do we use it?

6 days ago
PandaSurvive:

um

6 days ago
PandaSurvive:

ohhhh

6 days ago
PandaSurvive:

y-2= (x-(-3))

6 days ago
Shadow:

Good

6 days ago
Shadow:

Just remember to add in our slope :)

6 days ago
PandaSurvive:

1/3

6 days ago
Shadow:

Our perpendicular slope .-.

6 days ago
PandaSurvive:

oh -3 x'D

6 days ago
Shadow:

Haha xD

6 days ago
PandaSurvive:

i got y=-3x-7

6 days ago
Shadow:

Correct, good job )

6 days ago
Shadow:

lol, botched smile .-.

6 days ago
PandaSurvive:

thanks cx

6 days ago
Shadow:

haha no problem xD

6 days ago
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