What is f(x) = 7x2 + 42x written in vertex form? f(x) = 7(x + 6)2 – 6 f(x) = 7(x + 6)2 – 42 f(x) = 7(x + 3)2 – 9 f(x) = 7(x + 3)2 – 63
Well for starters cross out C) and D) and tell me what do you think it is
A
If that's what u think it is, than go for it
f(x) = 7x2 + 42x factor out the 7 to get f(x) = 7(x^2+6x) divide the b term by 2 and square the result to get 9 (this will create a perfect square) add 9 to the inside of the brackets 7(x^2+6x+9) subtract 7*9 from the outside to keep the equation equal 7(x^2+6x+9) - 63 then finish up the factorization
x = -6 x = 0 Reformatting the input : Changes made to your input should not affect the solution: (1): "x2" was replaced by "x^2". Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : 0-(7*x^2+42*x)=0
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