Question

http://prntscr.com/hd4v0u

Answer 1

@sammixboo

Answer 2

@Shadow

Answer 3

is it +10 +11 +12+13+14+15 etc.

Answer 4

@dude

Answer 5

Do you know how to write an exponential function?

Answer 6

no

Answer 7

The form looks like this:

\[f(x) = ab ^{x} \]

Where a is our starting value, and b is our common ratio between our y values.

Our starting value is the number in the set of y values that corresponds with x at zero. Can you identify the starting value?

Answer 8

100?

Answer 9

Correct.

Answer 10

Now as for our common ratio, there is a simple way to discover it.

Simple look at our y values. We have 100, 110, and 121. Use this formula.

\[b = \frac{ y _{2} }{ y _{1}}\]

Remember that b is our common ratio between our y values. You can solve for this by dividing any number in the our set of y values, by the number that came before it. This gives us the number by which you multiply, to get the next number.

Answer 11

so 110 / 100?

Answer 12

Does that make sense?

Answer 13

Correct

Answer 14

1.1

Answer 15

You have a and b, can you put the exponential function together now?

Answer 16

f(x)=100 x 1.1?

Answer 17

Close

\[f(x) = 100(\frac{ 11 }{ 10 })^{x} \]

or

\[f(x) = 100(1.1)^{x} \]

Some teachers may prefer it in fraction form.

Answer 18

is the x the year ?

Answer 19

Now that we have our exponential function, try input any x value (years) into our x, and solve for an output (which would give us the number of trucks registered in a year).

Answer 20

ok

Answer 21

990? if it is 9 years

Answer 22

Remember that we are taking it to the power of x, not multiplying it by x.

Answer 23

\[1^3 = 1 \times 1 \times 1 \neq 1 \times 3\]

Answer 24

oops XD

Answer 25

235.794769

Answer 26

Correct :)

Answer 27

236 for rounding