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Chemistry 48 Online
princeevee:

: For each chemical equation below, write the number of product molecules that will form from the reaction. Then, circle the limiting reactant. (Note: The coefficients in front of the reactants indicate the number of reactant molecules or atoms present.) A. 5C + 6O2  _______ CO2 B. 4Na + 8Cl2  _______ NaCl C. 3CO2 + 4H2O  _______ H2CO3 D. 7N2 + 9H2  _______ NH3 E. 10Zn + 16HCl  _______ ZnCl2 + _______ H2

princeevee:

@JustSaiyan

princeevee:

squares are suppose to be arrows pointing right

princeevee:

@Vocaloid

Vocaloid:

A. 5C + 6O2  _______ CO2 if you only have 5 molecules of C then how many CO2 molecules can you make?

Vocaloid:

each CO2 molecule needs 1 molecule of carbon so if you only have 5 molecules of C then how many molecules of CO2 can you make?

princeevee:

i would guess five then

Vocaloid:

good for B) B. 4Na + 8Cl2  _______ NaCl you have 4 atoms of Na and 8*2 = 16 atoms of Cl so how many molecules of NaCl can you make if each molecule of NaCl needs 1 Na and 1 Cl atom?

princeevee:

seven?

Vocaloid:

think of it like making a hot dog - if you have 4 hot dogs + 8 buns, you can only make 4 hot dogs since each hot dog requires 1 hot dog + 1 bun, and you can't make half a hot dog

Vocaloid:

if NaCl requires 1 Na and 1 Cl, and we only have 4 Na atoms and 8 Cl atoms how many NaCl can we make?

princeevee:

4

Vocaloid:

good, only 4 NaCl molecules

Vocaloid:

C. 3CO2 + 4H2O  _______ H2CO3 this one is a little harder; H2CO3 requires 3 oxygen atoms, 2 hydrogen, 1 carbon on the left side we have: 3 carbons, 8 hydrogens, 10 oxygens our limiting reactant is carbon - we can only make 3 molecules of H2CO3 since that requires 3 molecules carbon + 6 hydrogen + 9 oxygen, any more than this and we'd run out of carbon so 3 molecules of H2CO3 for C

Vocaloid:

D. 7N2 + 9H2  _______ NH3 14 molecules of nitrogen + 18 molecules of hydrogen on the left side if NH3 requires 1 nitrogen and 3 hydrogens, how many whole NH3 molecules can we make?

princeevee:

8

Vocaloid:

note: 8 NH3 would require 24 hydrogen atoms and we only have 18 hydrogen atoms the answer is a little lower than 8

princeevee:

oh?

princeevee:

6?

Vocaloid:

good, 6

Vocaloid:

E. 10Zn + 16HCl  _______ ZnCl2 + _______ H2 we are given: 10 Zn atoms, 16 H atoms, 16 Cl atoms the output requires 1 Zn atom, 2 Cl atoms, 2 H atoms - how many copies of the product can we make with our given atoms?

Vocaloid:

as a hint: we have 16 H atoms and the product H2 requires 2 hydrogen atoms - how many molecules of H2 can we make?

princeevee:

8?

princeevee:

for both?

princeevee:

1. What mass of H2O will be produced if 9.5 g of H2 reacts with 1.2 g of O2? __ H2 + __ O2  __ H2O 2. If 1.85 g of Mg(OH)2 reacts with 3.71 g of HCl, how much MgCl2 is produced? What is the limiting reactant? __ Mg(OH)2 + __ HCl  __ MgCl2 + __ H2O 3. What mass of potassium hydroxide is formed when 8.2 g of potassium oxide is added to 1.3 g of water? __ K2O + __ H2O  __ KOH 4. What mass of aluminum chloride could be made from 8.1 g of aluminum and 4.2 L of chlorine at STP? __ Al + __ Cl2  __ AlCl3 5. Determine the percent yield for the reaction between 3.74 g of Na and excess O2 if 5.34 g of Na2O2 is recovered. 6. Determine the percent yield for the reaction between 6.92 g of K and 4.28 g of O2 if 7.36 g of K2O is produced. 7. Determine the percent yield for the reaction between 28.1 g of Sb4O6 and excess C if 17.3 g of Sb is recovered along with an unknown amount of CO. 8. Determine the percent yield for the reaction between 45.9 g of NaBr and excess chlorine gas to produce 12.8 g of NaCl and an unknown quantity of bromine gas.

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