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Use the quadratic equation
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@TheSmartOne
You can use the subtraction method here
You want me to explain it step by step? @mikewwe13
ight
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ight man
wait you're doing the quadratic formula?
yea
Oh man than thats easy x'd alright
Alright so basically you know the Quadratic formula: \(ax^2 + bx+c=0\) Find a, b, c.
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As I already have shown the formula ax.. "a"=2; "bx":b=-4 and "c":y-5 Now put them in the quadratic formulaa
\[x=\frac{ \sqrt{(-4)^2-4*2(y-5)} }{ 2*2 }\]
y = -2 (x + 2 - 4)^2 + y - 5
Now solve in the square root first start from \(-4*2(y-5)\) than as also \(-4)^2\) square root it and add
jfc i forgot the \(4\pm\) in front of the quadratic formula
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Anyways as you solve this out your answer should be: \[x=4\pm2\frac{ \sqrt{2(7-y)} }{ 4 }\]
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