mikewwe13:

Use the quadratic equation

8 months ago
mikewwe13:
8 months ago

mikewwe13:

@TheSmartOne

8 months ago
alones:

You can use the subtraction method here

8 months ago
alones:

You want me to explain it step by step? @mikewwe13

8 months ago
mikewwe13:

ight

8 months ago
mikewwe13:

ight man

8 months ago
alones:

wait you're doing the quadratic formula?

8 months ago
mikewwe13:

yea

8 months ago
alones:

Oh man than thats easy x'd alright

8 months ago
alones:

Alright so basically you know the Quadratic formula: \(ax^2 + bx+c=0\) Find a, b, c.

8 months ago
alones:

As I already have shown the formula ax.. "a"=2; "bx":b=-4 and "c":y-5 Now put them in the quadratic formulaa

8 months ago
alones:

\[x=\frac{ \sqrt{(-4)^2-4*2(y-5)} }{ 2*2 }\]

8 months ago
mikewwe13:

y = -2 (x + 2 - 4)^2 + y - 5

8 months ago
alones:

Now solve in the square root first start from \(-4*2(y-5)\) than as also \(-4)^2\) square root it and add

8 months ago
alones:

jfc i forgot the \(4\pm\) in front of the quadratic formula

8 months ago
alones:

Anyways as you solve this out your answer should be: \[x=4\pm2\frac{ \sqrt{2(7-y)} }{ 4 }\]

8 months ago