need help with checking answers and #10 and 12 https://ibb.co/gLvnHx
#10 is a 30-60-90 Triangle Sides Opposite to Angles 90 - 2a 60 - a sqrt 3 30 - a They give the hypotenuse, which is 2x You can solve for y, the side opposite to angle 30 You can do this by dividing (4 sqrt 3) by 2. From 2a -> a \[\frac{ 4 \sqrt 3 }{ 2 } = y\]
y = a as per the 30 60 90 rule The side opposite to the angle 60 is a sqrt 3 So we can do the following, \[a \sqrt 3\] \[a = \frac{ 4 \sqrt 3}{ 2 }\] \[(\frac{ 4 \sqrt 3 }{ 2}) \sqrt 3\] Basically substituting a in. Then we simplify \[\frac{ 4(3) }{2 } = \frac{ 12 }{ 2 } = 6\]
Remember that \[\sqrt x \times \sqrt x = x\]
It seems that your main error though for 10 was putting the wrong values for the sides. You had x for the hypotenuse, 2x for the angle opposite to 60, and x sqrt 3for the angle opposite to 30.
In actuality it's hypotenuse - 2x 60 - x sqrt 3 30 - x
so for 10 is th e answer 6 or (4 square root 3 over 2) square rooted by 3
Correct, for x. \[y = \frac{ 4 \sqrt 3 }{ 2 }\]
then where did the 6 come from
\[6 = (\frac{ 4 \sqrt 3 }{ 2 }) \sqrt 3\]
Do you understand?
oh yea i was just confused bc i thought u meant 6 was the answer
wait so the answer is 6= (4 square 3 over 2) square ?
\[x = (\frac{ 4 \sqrt 3 }{ 2 }) \sqrt 3\] \[y = \frac{ 4 \sqrt 3 }{ 2 }\]
x also equals 6
6 is better though, since it's simplified.
so x is 6?
yus
so u don't have to write 6= (4 square 3 over 2) square ?
nope
All good?
Or is there another one you need help with?
can check if 8 is correct
|dw:1521605137106:dw|
This means: |dw:1521605198277:dw|
So we can do \[7 = x \sqrt 3\] \[\frac{ 7 }{ \sqrt 3} = x\] \[\frac{ \sqrt 3 }{ \sqrt 3 } \times (\frac{ 7 }{ \sqrt 3 }) = x\] \[\frac{ 7 \sqrt 3 }{ 3} = x\]
\[x = b = \frac{ 7 \sqrt 3 }{ 3 }\]
\[2x = a = 2(\frac{ 7 \sqrt 3 }{ 3 })\]
\[a = \frac{ 14 \sqrt 3 }{ 3}\]
thank you
No problem. All done?
yes
Haha, it seems you already had those answers. But you wrote the values wrong for each side. Don't know how that happened xD
no
|dw:1521605615941:dw| That's what you had on your paper
What's in bold black
I think you know how to do these problems. Just have to set them up correctly.
yea i just confused setting it up
If you ever need help, I am usually on around this time or a bit later.
ok thanks
There are some other cool math helpers too. Glad I could help.
When you do need help, just tag me or one of these guys. @Shadow @Vocaloid @563blackghost @TheSmartOne
ok
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