Juila12001:

need help with checking answers and #10 and 12 https://ibb.co/gLvnHx

1 month ago
Shadow:

#10 is a 30-60-90 Triangle Sides Opposite to Angles 90 - 2a 60 - a sqrt 3 30 - a They give the hypotenuse, which is 2x You can solve for y, the side opposite to angle 30 You can do this by dividing (4 sqrt 3) by 2. From 2a -> a \[\frac{ 4 \sqrt 3 }{ 2 } = y\]

1 month ago
Shadow:

y = a as per the 30 60 90 rule The side opposite to the angle 60 is a sqrt 3 So we can do the following, \[a \sqrt 3\] \[a = \frac{ 4 \sqrt 3}{ 2 }\] \[(\frac{ 4 \sqrt 3 }{ 2}) \sqrt 3\] Basically substituting a in. Then we simplify \[\frac{ 4(3) }{2 } = \frac{ 12 }{ 2 } = 6\]

1 month ago
Shadow:

Remember that \[\sqrt x \times \sqrt x = x\]

1 month ago
Shadow:

It seems that your main error though for 10 was putting the wrong values for the sides. You had x for the hypotenuse, 2x for the angle opposite to 60, and x sqrt 3for the angle opposite to 30.

1 month ago
Shadow:

In actuality it's hypotenuse - 2x 60 - x sqrt 3 30 - x

1 month ago
Juila12001:

so for 10 is th e answer 6 or (4 square root 3 over 2) square rooted by 3

1 month ago
Shadow:

Correct, for x. \[y = \frac{ 4 \sqrt 3 }{ 2 }\]

1 month ago
Juila12001:

then where did the 6 come from

1 month ago
Shadow:

\[6 = (\frac{ 4 \sqrt 3 }{ 2 }) \sqrt 3\]

1 month ago
Shadow:

Do you understand?

1 month ago
Juila12001:

oh yea i was just confused bc i thought u meant 6 was the answer

1 month ago
Juila12001:

wait so the answer is 6= (4 square 3 over 2) square ?

1 month ago
Shadow:

\[x = (\frac{ 4 \sqrt 3 }{ 2 }) \sqrt 3\] \[y = \frac{ 4 \sqrt 3 }{ 2 }\]

1 month ago
Shadow:

x also equals 6

1 month ago
Shadow:

6 is better though, since it's simplified.

1 month ago
Juila12001:

so x is 6?

1 month ago
Shadow:

yus

1 month ago
Juila12001:

so u don't have to write 6= (4 square 3 over 2) square ?

1 month ago
Shadow:

nope

1 month ago
Shadow:

All good?

1 month ago
Shadow:

Or is there another one you need help with?

1 month ago
Juila12001:

can check if 8 is correct

1 month ago
Shadow:

|dw:1521605137106:dw|

1 month ago
Shadow:

This means: |dw:1521605198277:dw|

1 month ago
Shadow:

So we can do \[7 = x \sqrt 3\] \[\frac{ 7 }{ \sqrt 3} = x\] \[\frac{ \sqrt 3 }{ \sqrt 3 } \times (\frac{ 7 }{ \sqrt 3 }) = x\] \[\frac{ 7 \sqrt 3 }{ 3} = x\]

1 month ago
Shadow:

\[x = b = \frac{ 7 \sqrt 3 }{ 3 }\]

1 month ago
Shadow:

\[2x = a = 2(\frac{ 7 \sqrt 3 }{ 3 })\]

1 month ago
Shadow:

\[a = \frac{ 14 \sqrt 3 }{ 3}\]

1 month ago
Juila12001:

thank you

1 month ago
Shadow:

No problem. All done?

1 month ago
Juila12001:

yes

1 month ago
Shadow:

Haha, it seems you already had those answers. But you wrote the values wrong for each side. Don't know how that happened xD

1 month ago
Juila12001:

no

1 month ago
Shadow:

|dw:1521605615941:dw| That's what you had on your paper

1 month ago
Shadow:

What's in bold black

1 month ago
Shadow:

I think you know how to do these problems. Just have to set them up correctly.

1 month ago
Juila12001:

yea i just confused setting it up

1 month ago
Shadow:

If you ever need help, I am usually on around this time or a bit later.

1 month ago
Juila12001:

ok thanks

1 month ago
Shadow:

There are some other cool math helpers too. Glad I could help.

1 month ago
Shadow:

When you do need help, just tag me or one of these guys. @Shadow @Vocaloid @563blackghost @TheSmartOne

1 month ago
Juila12001:

ok

1 month ago
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