need help with checking answers and #10 and 12 https://ibb.co/gLvnHx

1 year ago#10 is a 30-60-90 Triangle Sides Opposite to Angles 90 - 2a 60 - a sqrt 3 30 - a They give the hypotenuse, which is 2x You can solve for y, the side opposite to angle 30 You can do this by dividing (4 sqrt 3) by 2. From 2a -> a \[\frac{ 4 \sqrt 3 }{ 2 } = y\]

1 year agoy = a as per the 30 60 90 rule The side opposite to the angle 60 is a sqrt 3 So we can do the following, \[a \sqrt 3\] \[a = \frac{ 4 \sqrt 3}{ 2 }\] \[(\frac{ 4 \sqrt 3 }{ 2}) \sqrt 3\] Basically substituting a in. Then we simplify \[\frac{ 4(3) }{2 } = \frac{ 12 }{ 2 } = 6\]

1 year agoRemember that \[\sqrt x \times \sqrt x = x\]

1 year agoIt seems that your main error though for 10 was putting the wrong values for the sides. You had x for the hypotenuse, 2x for the angle opposite to 60, and x sqrt 3for the angle opposite to 30.

1 year agoIn actuality it's hypotenuse - 2x 60 - x sqrt 3 30 - x

1 year agoso for 10 is th e answer 6 or (4 square root 3 over 2) square rooted by 3

1 year agoCorrect, for x. \[y = \frac{ 4 \sqrt 3 }{ 2 }\]

1 year agothen where did the 6 come from

1 year ago\[6 = (\frac{ 4 \sqrt 3 }{ 2 }) \sqrt 3\]

1 year agoDo you understand?

1 year agooh yea i was just confused bc i thought u meant 6 was the answer

1 year agowait so the answer is 6= (4 square 3 over 2) square ?

1 year ago\[x = (\frac{ 4 \sqrt 3 }{ 2 }) \sqrt 3\] \[y = \frac{ 4 \sqrt 3 }{ 2 }\]

1 year agox also equals 6

1 year ago6 is better though, since it's simplified.

1 year agoso x is 6?

1 year agoyus

1 year agoso u don't have to write 6= (4 square 3 over 2) square ?

1 year agonope

1 year agoAll good?

1 year agoOr is there another one you need help with?

1 year agocan check if 8 is correct

1 year ago|dw:1521605137106:dw|

1 year agoThis means: |dw:1521605198277:dw|

1 year agoSo we can do \[7 = x \sqrt 3\] \[\frac{ 7 }{ \sqrt 3} = x\] \[\frac{ \sqrt 3 }{ \sqrt 3 } \times (\frac{ 7 }{ \sqrt 3 }) = x\] \[\frac{ 7 \sqrt 3 }{ 3} = x\]

1 year ago\[x = b = \frac{ 7 \sqrt 3 }{ 3 }\]

1 year ago\[2x = a = 2(\frac{ 7 \sqrt 3 }{ 3 })\]

1 year ago\[a = \frac{ 14 \sqrt 3 }{ 3}\]

1 year agothank you

1 year agoNo problem. All done?

1 year agoyes

1 year agoHaha, it seems you already had those answers. But you wrote the values wrong for each side. Don't know how that happened xD

1 year agono

1 year ago|dw:1521605615941:dw| That's what you had on your paper

1 year agoWhat's in bold black

1 year agoI think you know how to do these problems. Just have to set them up correctly.

1 year agoyea i just confused setting it up

1 year agoIf you ever need help, I am usually on around this time or a bit later.

1 year agook thanks

1 year agoThere are some other cool math helpers too. Glad I could help.

1 year agoWhen you do need help, just tag me or one of these guys. @Shadow @Vocaloid @563blackghost @TheSmartOne

1 year agook

1 year ago