Juila12001:

need help with checking answers and #10 and 12 https://ibb.co/gLvnHx

8 months ago
Shadow:

#10 is a 30-60-90 Triangle Sides Opposite to Angles 90 - 2a 60 - a sqrt 3 30 - a They give the hypotenuse, which is 2x You can solve for y, the side opposite to angle 30 You can do this by dividing (4 sqrt 3) by 2. From 2a -> a \[\frac{ 4 \sqrt 3 }{ 2 } = y\]

8 months ago
Shadow:

y = a as per the 30 60 90 rule The side opposite to the angle 60 is a sqrt 3 So we can do the following, \[a \sqrt 3\] \[a = \frac{ 4 \sqrt 3}{ 2 }\] \[(\frac{ 4 \sqrt 3 }{ 2}) \sqrt 3\] Basically substituting a in. Then we simplify \[\frac{ 4(3) }{2 } = \frac{ 12 }{ 2 } = 6\]

8 months ago
Shadow:

Remember that \[\sqrt x \times \sqrt x = x\]

8 months ago
Shadow:

It seems that your main error though for 10 was putting the wrong values for the sides. You had x for the hypotenuse, 2x for the angle opposite to 60, and x sqrt 3for the angle opposite to 30.

8 months ago
Shadow:

In actuality it's hypotenuse - 2x 60 - x sqrt 3 30 - x

8 months ago
Juila12001:

so for 10 is th e answer 6 or (4 square root 3 over 2) square rooted by 3

8 months ago
Shadow:

Correct, for x. \[y = \frac{ 4 \sqrt 3 }{ 2 }\]

8 months ago
Juila12001:

then where did the 6 come from

8 months ago
Shadow:

\[6 = (\frac{ 4 \sqrt 3 }{ 2 }) \sqrt 3\]

8 months ago
Shadow:

Do you understand?

8 months ago
Juila12001:

oh yea i was just confused bc i thought u meant 6 was the answer

8 months ago
Juila12001:

wait so the answer is 6= (4 square 3 over 2) square ?

8 months ago
Shadow:

\[x = (\frac{ 4 \sqrt 3 }{ 2 }) \sqrt 3\] \[y = \frac{ 4 \sqrt 3 }{ 2 }\]

8 months ago
Shadow:

x also equals 6

8 months ago
Shadow:

6 is better though, since it's simplified.

8 months ago
Juila12001:

so x is 6?

8 months ago
Shadow:

yus

8 months ago
Juila12001:

so u don't have to write 6= (4 square 3 over 2) square ?

8 months ago
Shadow:

nope

8 months ago
Shadow:

All good?

8 months ago
Shadow:

Or is there another one you need help with?

8 months ago
Juila12001:

can check if 8 is correct

8 months ago
Shadow:

|dw:1521605137106:dw|

8 months ago
Shadow:

This means: |dw:1521605198277:dw|

8 months ago
Shadow:

So we can do \[7 = x \sqrt 3\] \[\frac{ 7 }{ \sqrt 3} = x\] \[\frac{ \sqrt 3 }{ \sqrt 3 } \times (\frac{ 7 }{ \sqrt 3 }) = x\] \[\frac{ 7 \sqrt 3 }{ 3} = x\]

8 months ago
Shadow:

\[x = b = \frac{ 7 \sqrt 3 }{ 3 }\]

8 months ago
Shadow:

\[2x = a = 2(\frac{ 7 \sqrt 3 }{ 3 })\]

8 months ago
Shadow:

\[a = \frac{ 14 \sqrt 3 }{ 3}\]

8 months ago
Juila12001:

thank you

8 months ago
Shadow:

No problem. All done?

8 months ago
Juila12001:

yes

8 months ago
Shadow:

Haha, it seems you already had those answers. But you wrote the values wrong for each side. Don't know how that happened xD

8 months ago
Juila12001:

no

8 months ago
Shadow:

|dw:1521605615941:dw| That's what you had on your paper

8 months ago
Shadow:

What's in bold black

8 months ago
Shadow:

I think you know how to do these problems. Just have to set them up correctly.

8 months ago
Juila12001:

yea i just confused setting it up

8 months ago
Shadow:

If you ever need help, I am usually on around this time or a bit later.

8 months ago
Juila12001:

ok thanks

8 months ago
Shadow:

There are some other cool math helpers too. Glad I could help.

8 months ago
Shadow:

When you do need help, just tag me or one of these guys. @Shadow @Vocaloid @563blackghost @TheSmartOne

8 months ago
Juila12001:

ok

8 months ago