Taco:

Find the horizontal asymptote

7 months ago
Taco:

I think I will try to use the tool u said.

7 months ago
Taco:

\[f(x) = \frac{ 8x -7 }{ 4x + 3 }\]

7 months ago
Taco:

thats what on my paper

7 months ago
Hero:

Okay, so to find the horizontal asymptote, you simply divide the coefficients of the terms with highest degree. In this case the terms with the highest degree are \(8x\) and \(4x\). \(\dfrac{8x}{4x} = ?\)

7 months ago
Taco:

2?

7 months ago
Hero:

Correct.

7 months ago
Taco:

that was a bit easier than I thought

7 months ago
Taco:

do they need to be the same degree?

7 months ago
Hero:

You just simply circle the coefficient terms with the highest degree in both the numerator and denominator and then divide them. That is it.

7 months ago
Hero:

So actually, we would only divide the 8 and 4.

7 months ago
Taco:

okay wow thats pretty simple

7 months ago
Hero:

But if the degree of the numerator is higher than the degree of the denominator, then there will not be a horizontal asymptote.

7 months ago
Taco:

like x^2/x ?

7 months ago
Hero:

Exactly

7 months ago
Taco:

I think I got this one then. will skip to some other ones I don't know.

7 months ago