Find the horizontal asymptote

1 year agoI think I will try to use the tool u said.

1 year ago\[f(x) = \frac{ 8x -7 }{ 4x + 3 }\]

1 year agothats what on my paper

1 year agoOkay, so to find the horizontal asymptote, you simply divide the coefficients of the terms with highest degree. In this case the terms with the highest degree are \(8x\) and \(4x\). \(\dfrac{8x}{4x} = ?\)

1 year ago2?

1 year agoCorrect.

1 year agothat was a bit easier than I thought

1 year agodo they need to be the same degree?

1 year agoYou just simply circle the coefficient terms with the highest degree in both the numerator and denominator and then divide them. That is it.

1 year agoSo actually, we would only divide the 8 and 4.

1 year agookay wow thats pretty simple

1 year agoBut if the degree of the numerator is higher than the degree of the denominator, then there will not be a horizontal asymptote.

1 year agolike x^2/x ?

1 year agoExactly

1 year agoI think I got this one then. will skip to some other ones I don't know.

1 year ago