Find the horizontal asymptote
I think I will try to use the tool u said.
\[f(x) = \frac{ 8x -7 }{ 4x + 3 }\]
thats what on my paper
Okay, so to find the horizontal asymptote, you simply divide the coefficients of the terms with highest degree. In this case the terms with the highest degree are \(8x\) and \(4x\). \(\dfrac{8x}{4x} = ?\)
2?
Correct.
that was a bit easier than I thought
do they need to be the same degree?
You just simply circle the coefficient terms with the highest degree in both the numerator and denominator and then divide them. That is it.
So actually, we would only divide the 8 and 4.
okay wow thats pretty simple
But if the degree of the numerator is higher than the degree of the denominator, then there will not be a horizontal asymptote.
like x^2/x ?
Exactly
I think I got this one then. will skip to some other ones I don't know.
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