Question

i need some answers checked

Answer 1

@Vocaloid my choice was the top right one

Answer 2

The leg and hypotenuse cannot both be 6. Remember what we said earlier: the leg of a 45-45-90 triangle is the hypotenuse divided by sqrt(2)

Answer 3

so it was the top left one?

Answer 4

Hypotenuse ~divided~ by sqrt(2) not multiplied.

Answer 5

so the bottom right one, as 3 is a multiple of 6?

Answer 6

Yes

6/sqrt(2) = 3sqrt(2)

Answer 7

i got A on this one

Answer 8

Nope

First calculate the side length of the square using perimeter = 4s

Then multiply by sqrt(2) because hypotenuse = leg * sqrt(2)

Answer 9

If the perimeter of a square is 10, then side length =?

Answer 10

Perimeter = 4* side length

Solve for side length

Answer 11

so if the perimeter is 4, wouldnt that make it 1.8?

Answer 12

The perimeter is not 4

Please re-read the original problem

Answer 13

oh, right...

Answer 14

A square has four equal sides right? So the side length = perimeter/4

Answer 15

10/4=2.5

Answer 16

Good now multiply that by sqrt(2)

Answer 17

6.25

Answer 18

Check your calculations again

Remember order of operations. Take the square root of 2 first and then multiply by 6

Answer 19

*multiply by 2.5 not 6

Answer 20

24?

Answer 21

hang on, i might've did it wrong again

Answer 22

Press the square root button, then 2

Press the enter button

Then multiply by 2.5

Answer 23

so 4, x 2.5 = 10

Answer 24

Square root is not the same thing as squaring

So the square root of 2 is not 4

Answer 25

Try this

2^(0.5) * 2.5

Answer 26

3.53

Answer 27

Good

3.5 is the only solution close enough so that's our answer

Answer 28

what i got on this, was 16.

Answer 29

Hm not quite, 16 would be the value of x not y

To get y you just need to multiply 16 by sqrt(3) since y is the side across the 60 degree side

Answer 30

so D?

Answer 31

Good

Answer 32

i chose the last one, as an isosceles is suppose to have two congruent sides, right?

Answer 33

Good

Answer 34

i chose C for this one

Answer 35

Hm not quite, 8 would be for a 30-60-90 triangle

For a 45-45-90 triangle hypotenuse = leg * sqrt(2) =?

Answer 36

8?

Answer 37

or at least, 16?

Answer 38

The leg is 4 right?

So sqrt(2) * 4 =?

Answer 39

5.6

Answer 40

so b

Answer 41

Good

Answer 42

false

Answer 43

Good

Answer 44

A?

Answer 45

The height of the wall is basically one leg of a right triangle so by definition it cannot be longer than the hypotenuse

For a 45-45-90 triangle

Leg = hypotenuse / sqrt(2) =?

Answer 46

I mean, even without doing any calculations there's only one choice less than the hypotenuse 13

Answer 47

9.2?

Answer 48

Yup good

Answer 49

the top right one?

Answer 50

Good

Answer 51

XZ

Answer 52

Hm that's a very good guess but XZ is the hypotenuse which is not considered a leg

So between the other two sides which one do you think is longer?

Answer 53

XY

Answer 54

Good so xy is your sol 'n

Answer 55

my choice is C

Answer 56

Hm not quite

You're just gonna count the number of horizontal spaces between M and N

Answer 57

in other words just subtract the x-coordinates of M and N

Answer 58

* M and F I mean

Answer 59

so you have a right triangle and you are given the hypotenuse and one leg

so try plugging them into

a^2 + b^2 = c^2

and solving for the missing leg

Answer 60

1300

Answer 61

36.05

Answer 62

hm, not quite, remember we have the hypotenuse (30) and one leg (20)

so 30^2 = a^2 + 20^2 solve for a

Answer 63

500

Answer 64

almost, that's a^2 so you'd just have to take the square root of 500

Answer 65

22.3

Answer 66

almost, the square root of 500 is 22.360 something so it rounds up to 22.4 not 22.3

Answer 67

so thats my answer?

Answer 68

yes

Answer 69

this is true

Answer 70

hm, be careful, it's the sum of the squares of the lengths, not just the lengths

so false

Answer 71

the top right one

Answer 72

hm, not quite, a good thing to remember is that the hypotenuse is the biggest side so it has to be bigger than 10

a^2 + b^2 = c^2

plug in your legs (10 and 4) and solve for c

Answer 73

so the bottom left one? that's what i got from it

Answer 74

remember to square the sides before adding them

10^2 + 4^2 = ?

Answer 75

116

Answer 76

good and what's the square root of that?

Answer 77

i disconnected, sorry

Answer 78

10.7

Answer 79

good so 10.77 is the closest and thus your sol'n

Answer 80

24?

Answer 81

good

Answer 82

when you have a diagonal through a square you get two 45-45-90 triangles

as usual

leg = hypotenuse/sqrt(2) = ?

Answer 83

3.5?

Answer 84

12.25 i meant

Answer 85

hm not quite

what is 3.5 divided by sqrt(2)?

remember order of operations

Answer 86

I don't really know how to explain this any better haha

you just need to type 3.5/√(2)

Answer 87

2.47

Answer 88

good but they want the nearest tenth so 2.5

Answer 89

7?

Answer 90

hm, not 7.

remember you cannot just add the side lengths together, you have to use the formula a^2 + b^2 = c^2 to solve for c

Answer 91

when you sketched the triangle you got side lengths 3 and 4 right? plug those in as your a and b values then solve for c.

Answer 92

5

Answer 93

good so 5 = your sol'n

Answer 94

3?

Answer 95

not quite

what are the x-coordinates of B and Z?

Answer 96

-9 and -5

Answer 97

good so what's the difference of -9 and -5?

Answer 98

-4 apart?

Answer 99

good but since it's distance we take the absolute value of that to get 4 = your sol'n

Answer 100

C?

Answer 101

not quite

you are given the hypotenuse and one leg

a^2 + b^2 = c^2
solve for the missing leg

remember that c is the hypotenuse and (a and b) are the legs

Answer 102

the hypotenuse is 65 and one of the legs is 33 right?

therefore

33^2 + a^2 = 65^2 so solve for (a)

Answer 103

49?

Answer 104

33^2 + a^2 = 65^2

subtract 33^2 from both sides to get

a^2 = 65^2 - 33^2

therefore a = ?

Answer 105

5134

Answer 106

that's a^2

so if a^2 = 5134
a = ?

Answer 107

71.6

Answer 108

wait a minute how did you get 5134

Answer 109

what's 65^2 - 33^2?

Answer 110

65^2 = ?
33^2 = ?

calculate the two values separately

then subtract them

Answer 111

3136

Answer 112

56

Answer 113

good so 56 = your sol'n

Answer 114

17?

Answer 115

good

Answer 116

top right?

Answer 117

hm not quite

you have the opposite and adjacent, what trig ratio is this?

Answer 118

uh...

Answer 119

dang, i just forgot trig...

Answer 120

as I stated before you have the adjacent and opposite sides
which trig ratio is appropriate? check the diagram

Answer 121

which trig ratio involves the opposite and adjacent sides? check the red text

Answer 122

so you'd use tangent, right?

so you set up

tan(theta) = opposite/adjacent

plug in your values & solve for the missing side.

Answer 123

i got top left, for some reason, i dont think its right...

Answer 124

which side of the triangle is opposite to the angle? and which is the adjacent side?

Answer 125

the dotted one is adjacent, right?

Answer 126

the dotted side is the hypotenuse and thus is not included in this calculation.

Answer 127

sorry, i'm not working at full capacity...

Answer 128

i'll keep trying though

Answer 129

so there are only two other sides of the triangle are 21 and x

notice how the x side is the farthest across from the angle, so that's our opposite side

the 21 is next to the angle so that's our adjacent side

therefore tan(36) = x/21 solve for x

Answer 130

i am so sorry, i passed out...

Answer 131

@Vocaloid let us continue where we left off

Answer 132

sure
solving for x gives us tan(36) * 21 which you can then just plug into a calculator to get the sol'n

Answer 133

162

Answer 134

can you try putting in tan(36)

then multiply the result by 21 ?

Answer 135

still 162

Answer 136

oh wait your calculator is probably in radians mode

can you try changing it to degrees mode?

Answer 137

if you can't figure it out try typing in tan(36) * 21 into wolframalpha.com

Answer 138

15.25?

Answer 139

good

it rounds up to 15.26 actually so 15.26 is your sol'n

Answer 140

@Vocaloid

Answer 141

from the perspective of angle A

opposite/adjacent = ?

remember that the hypotenuse is not included

Answer 142

^ try to apply this logic to your triangle to figure out what the adjacent and opposite sides are

remember that the opposite side is the furthest away from the angle, and the adjacent side is closest w/o being the hypotenuse

Answer 143

still there? try to see which side is farthest away from angle A and which one is the closest to angle A

Answer 144

yeah, thinking

Answer 145

i somehow got the bottom left one

Answer 146

that's the adjacent over the opposite

tan is opposite over adjacent

Answer 147

the side farthest away from A is the 5 side
the side next to A is the 12 side

so opposite/adjacent = ?

Answer 148

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid
^ try to apply this logic to your triangle to figure out what the adjacent and opposite sides are

remember that the opposite side is the furthest away from the angle, and the adjacent side is closest w/o being the hypotenuse
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 149

therefore the opposite side is 5 and the adjacent side is 12

making tan = opposite/adjacent = 5/12 = your solution

gtg

Answer 150

sorry , see you later

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