eviant:

PLS HELP!!!

3 weeks ago
eviant:

1 attachment
3 weeks ago
eviant:

@Vocaloid

3 weeks ago
eviant:

@mhchen

3 weeks ago
dude:

Substitute the x and y that were given

3 weeks ago
eviant:

y=2, x=-4

3 weeks ago
dude:

Also \(x^{-n}=\frac{1}{x^n}\) n being any number Likewise \(\frac{1}{x^{-n}}=>x^n\)

3 weeks ago
dude:

Yes

3 weeks ago
eviant:

\[\frac{ 1 }{ 4 }\]-\[\frac{ 1 }{ 64 }\], 32

3 weeks ago
dude:

That is confusing to look at \(\large \frac{1}{2^{-2}x^{-3}y^5}\), \( x=2, y=-4\) \(\large \frac{1}{2^{-2}2^{-3}-4^5}\) \(\large \frac{1}{\color{red}{2^{-2}2^{-3}}-4^5}\) The red will flip to go on the numerator and will lose the - exponent

3 weeks ago
eviant:

\[\frac{ 1 }{ 4 }\],\[\frac{ 1 }{ 8 }\],-1024

3 weeks ago
dude:

Also quick note, if you want to copy the latex, right-click the math and Show Math As > Tex Commands 2pnCpc1TQeKTX3gEWa9m6g.png When pasting include `\( \)` in between

3 weeks ago
eviant:

@dude thanks how do I get the final answer

3 weeks ago
dude:

\(\large \frac{1}{2^{-2}2^{-3}-4^5}\) After flipping the numbers to the numerator =\(\large \frac{2^{2}2^{3}}{-4^5}\) \(2^2=4\) \(2^3=8\) and \(-4^5=-1024\)

3 weeks ago
dude:

\(\large \frac{4\cdot 8}{-1024}\) =\(\large -\frac{32}{1024}=>\boxed{\frac{1}{32}}\)

3 weeks ago
jhonyy9:

@dude pardon but the result is minus 1/32

3 weeks ago
jhonyy9:

@ThisGirlPretty do you agree it ?

3 weeks ago
dude:

Right, thank you \(\large -{\frac{1}{32}}\)

3 weeks ago
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