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Physics 90 Online
lowkey:

coulomb's law problem

lowkey:

1 attachment
lowkey:

@shadow @vocaloid

lowkey:

|dw:1552966872554:dw|

Shadow:

They gave you force

Shadow:

You're solving for charge which is above r^2 aka 0.1^2

lowkey:

|dw:1552967011427:dw|

lowkey:

the thing is, what if the charges arent equal

Shadow:

Also the charge of an electron is 1.60 x 10^-19 Coulombs

Shadow:

That'll be useful for the second part.

Shadow:

uh...what do you mean

lowkey:

iwannacry

lowkey:

ok whats the answer Let me work it out

Shadow:

Lowkey you just need to put numbers in the variables.

lowkey:

I got 2.24E-6

Shadow:

K so I just multiplied the force by the distance squared, divided by the constant and got 5 x 10^-12

Shadow:

I don't know how you got that number but the formula should look like this: \[F_{e} = k \frac{ q }{ r^2 }\] Where in this format, we're solving for the electrical force which is equal to Coulomb's constant multiplied by the charge divided by the distance squared.

Shadow:

Just make that negative since I just used the magnitude of the force (4.5).

lowkey:

1 attachment
lowkey:

Wouldn't there be two charges because there are two items?

lowkey:

Idk maybe I'm wrong, I took two NyQuils and three supplement pills

Shadow:

I know but we are not given the charges of either, and are solely seeking the charge of one object.

Shadow:

I remember using q singularly before in some instances. Here for electric field they illustrate the charge as being "Qsource" and not q times q, so there is validity for this.

lowkey:

oh

lowkey:

damn i dont have an eraser

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