Question

A student solved the following problem and made an error:

Triangles ABC and DEF. Angles A and F are congruent and measure 135 degrees. Coordinates for the vertices are at A 0, 2 and B 2, 4 and C 0, 0 and D 2, 0 and E 4, 4 and F 4, 2.

Line 1 Segment AC equals 2. Segment FE equals 2. Segment AC is congruent to segment FE
Line 2 ∠A ≅ ∠F
Line 3 Length of segment AB.
A (0, 2)
B (2, 4)
d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub 1 squared, d equals square root of quantity 0 minus 2 all squared plus quantity 2 minus 4 all squared, d equals square root of negative 2 squared plus negative 2 squared, d equals square root of 4 plus 4, d equals square root of 8
segment AB = 2.83
Line 4 Length of segment DE.
D (2, 0)
E (4, 4)
d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub squared, d equals square root of quantity 2 minus 4 all squared plus quantity 0 minus 4 all squared, d equals square root of negative 2 squared plus negative 4 squared, d equals square root of 4 plus 16, then d equals square root of 20
segment DE = 4.47
Line 5 segment AB is congruent with segment DE
Line 6 triangle ABC is congruent with triangle FDEby SAS

In which line did the student make the first mistake?

Answer 1

in the first line given that triangle ABC and triangle DEF with angles A and F congruents

so here is the first error ,how kis wrote given from this result angle A congruent angle D and not angle F

hope helped understandably