Question

can someone please help me

Answer 1

What is your question.

Answer 2

Given the function h(x) = 3(5)x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3.

Part A: Find the average rate of change of each section. (4 points)

Part B: How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other. (6 points)

Answer 3

Your teacher gave you \(h(x) = 3(5)^x\) is that correct?

Answer 4

its a type your answer

Answer 5

like i gotta type everything out

Answer 6

i didnt

Answer 7

part A)
rate of change formula for a function f(x), from x = a to x = b

\[= \frac{ f(b)-f(a) }{ b-a }\]

applying this to your problem: h(x) = 3(5)^x, Section A is from x = 0 to x = 1

in this case, your function is h(x) = 3(5)^x, and since it wants the change from 0 to 1, your a vale is 0, and your b-value is 1

plugging in:
rate of change\[= \frac{ h(1)-h(0) }{ 1-0 }\]
\[=\frac{ 3(5)^{1}-3(5)^{0} }{ 1-0 }=~?\]

repeat this process for Section B for x = 2 to x = 3.

part B)
How many times greater is the average rate of change of Section B than Section A?

calculate: \[\frac{ ( rate~of~change~for~sect.~B - rate~of~change~for~sect.~A) }{ rate~of~change~for~sect.~A }\]
to determine how much greater the section B change is, compared to section A's change

now, when it asks why one rate of change is greater than the other ---> think about your function h(x), and what values it takes when x is high vs. low

Answer 8

@mercury, I think for part B you just need to calculate

(rate of change for section B)/(rate of change for section A)

Answer 9

we're getting into nitpicky territory but since it says how many times **greater** you'd need to find the difference between B and A first

B/A would just be how many times *as* great

Answer 10

That's true, the language on these types of problems can be a bit strange, and you make a good point.