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Solve the problem. SAT verbal scores are normally distributed with a mean of 447 and a standard deviation of 96. Use the Empirical Rule to determine what percent of the scores lie between 447 and 543.
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Z-score formula: \[z = \frac{ x-µ }{ σ }\] where z is the z-score, x is the value being examined, µ is the mean, σ is the standard deviation calculate the z-score for x = 447, as well as x = 543, and use a calculator/z-table to find the associated probabilities. then subtract the two probabilities to get the % of scores between 447-543
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