Question

What value of x satisfies this equation?
1.5(4)^2x=12


Round your answer to the nearest hundredth.

The value of x is
.

Answer 1

@supie

Answer 2

May you post a screenshot of the question and upload it with "Attach File" please?

Answer 3

do u have a screen shot

Answer 4

Thank you.

Answer 5

ok so first thing you r going to have to distribute

Answer 6

Given\[1.5(4^{2x})=12\] Divide 1.5 from both sides\[\frac{ 1.5(4^{2x}) }{ 1.5 }=\frac{ 12 }{ 1.5 }\]\[4^{2x}=8\]Solve exponent \[4^{2x}=8\]Log from both sides\[\log(4^{2x})=\log (8)\]\[2x \times(\log (4))=\log(8)\]\[2x=\frac{ \log(8) }{ \log(4) }\]\[2x=1.5\]Divide 2 from both sides\[\frac{ 2x }{ 2 }=\frac{ 1.5 }{ 2}\] Therefore \[x=0.75\]

Answer 7

thank you

Answer 8

(: Anytime.