Question

Factor completely.

Answer 1

x^2-8x+15

Answer 2

Wrong subject this is math yikes

@dude

Answer 3

\(\color{#0cbb34}{\text{Originally Posted by}}\) @jhonyy9
try get two numbers what are sum -8 and product 15
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 4

x+y = -8
x*y = 15

can you solve this system ?

Answer 5

this is the easy way

but you can use the discriminant method to get the roots of a quadratic

Answer 6

what you wan use ?

Answer 7

the discriminant formula do you know ?

Answer 8

No

Answer 9

ok so than use the first what i ve wrote above - this is the easyst way

try get two numbers with sum -8 and product 15

Answer 10

@Allison any idea ?

Answer 11

That add up?

Answer 12

why ? this is easy

Answer 13

-4 times 2..? or addition that gets -8?

Answer 14

addition like x+y= -8

and product like x*y = 15

Answer 15

5 x 3
4+4

Answer 16

so than you get these two numbers these will be the roots of this quadratic but to write it completly factorized you need to know again the Viéte formula how can you rewrite a quadratic completly factorized than you know the roots of quadratic

@dude do you agree this pls ?

Answer 17

@Allison there are 4 numbers but you need just two

Answer 18

two numbers with sum -8 and product 15

Answer 19

Going to rephrase what jhonny said

Get two numbers that will multiply to 15

Once you have those, add *those numbers* up and check if it equals -8

Answer 20

Only 5 and 3

Answer 21

Yes, but you need to get to -8

Answer 22

(Use negatives)

Answer 23

-5 and -3?

Answer 24

ty. @dude

Answer 25

Yes

Now write it as
\((x-5)(x-3)\)